Walt and Mary are my Customers at this point.
To construct proper client relationships you need to: greet clients and approach them in a way that is herbal and suits the character scenario. show customers that you recognize what their desires are. be given that a few humans may not want your merchandise and concentrate on constructing relationships with people who do.
Use the time period clients, with an apostrophe before the “s” to expose a possessive form for a single consumer. Use the time period clients', with an apostrophe after the “s” to show the possessive plural shape of a couple of patrons. Do now not use an apostrophe if there's no possessive indication needed.
The definition of a consumer is a person who buys services or products from a store, restaurant, or different retail vendor. An example of a patron is someone who is going to an electronics save and buys a tv. (Casual) a person, mainly one engaging in a few types of interaction with others.
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Answer : The kinetic energy depends directly on the mass of a particle.
Explanation :
We know that the kinetic energy of any particle is given by :
Where,
m is the mass of an object.
v is the velocity with which it is moving
Kinetic energy is due to the motion of the particle.
So, the kinetic energy of a particle is directly proportional to its mass.
Hence, the conclusion of the question is if the mass of a particle is increases then its kinetic energy also increase.
<span>For hydrolysis to monosaccharides, one molecule of a disaccharide needs only one molecule of water.
C12H22O11 (sucrose) + H2O = C6H12O6 (glucose) + C6H12O6 (fructose)
Structurally, a disaccharide molecule may be viewed as a product formed by the condensation of two molecules of monosaccharides with the elimination of a water molecule. So, only one H2O molecule is needed for the reverse process.</span>
In other words a infinitesimal segment dV caries the charge
<span>dQ = ρ dV </span>
<span>Let dV be a spherical shell between between r and (r + dr): </span>
<span>dV = (4π/3)·( (r + dr)² - r³ ) </span>
<span>= (4π/3)·( r³ + 3·r²·dr + 3·r·(dr)² + /dr)³ - r³ ) </span>
<span>= (4π/3)·( 3·r²·dr + 3·r·(dr)² + /dr)³ ) </span>
<span>drop higher order terms </span>
<span>= 4·π·r²·dr </span>
<span>To get total charge integrate over the whole volume of your object, i.e. </span>
<span>from ri to ra: </span>
<span>Q = ∫ dQ = ∫ ρ dV </span>
<span>= ∫ri→ra { (b/r)·4·π·r² } dr </span>
<span>= ∫ri→ra { 4·π·b·r } dr </span>
<span>= 2·π·b·( ra² - ri² ) </span>
<span>With given parameters: </span>
<span>Q = 2·π · 3µC/m²·( (6cm)² - (4cm)² ) </span>
<span>= 2·π · 3×10⁻⁶C/m²·( (6×10⁻²m)² - (4×10⁻²m)² ) </span>
<span>= 3.77×10⁻⁸C </span>
<span>= 37.7nC</span>
Answer:
<u>Magnitude</u>
Explanation:
Each value in nature has a number part, called its magnitude and a dimension called its unit.
For example,
The length of an object is 10 cm. It means that 10 shows the magnitude of length and cm shows its unit.
