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hjlf
3 years ago
6

To describe velocity, you need to know ____. (1 point)

Physics
2 answers:
kati45 [8]3 years ago
8 0
The correct answer that would best complete the given statement above would be the first option. <span>To describe velocity, you need to know speed and direction. When we say velocity, this is the speed of something in a given direction. To solve for velocity, its formula is similar to speed which is distance over time, and just include the direction. Hope this answer helps.</span>
son4ous [18]3 years ago
3 0
<span>To describe velocity, you need to know speed and direction of motion.</span>
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What must the charge (sign and magnitude) of a 3.45 g particle be for it to remain stationary when placed in a downward-directed
Pani-rosa [81]

     charge must be equal to 5.74 ×10⁻⁵

 In the question it is said that the particle remains stationary which means the the net force on the particle is zero. So, the counterbalancing forces must be equal which means weight is equal to upward electric force.

     →    Fnet =0

     →    mg =  qE

 substituting the values we get :

         0.00345 × 9.81 =  q × 590

   →       q = 5.74 ×10⁻⁵

    Hence the charge must be equal to   5.74 ×10⁻⁵.

   Learn more about charges here:

          brainly.com/question/26092261

                    # SPJ4

8 0
1 year ago
Can you help me doing an essay about actual self​
Rudik [331]

Answer:

yes absolutely

Explanation:

why not

4 0
3 years ago
Which skateboarder has greater momentum?
Verizon [17]

Answer:

skateboard b

Explanation:

p=mv

skateboard a

p=(60kg)(1.5m/s)=90kg*m/s

skateboard b

p=(50kg)(2m/s)=100kg*m/s

5 0
3 years ago
what are the speeds of (a) a proton that is accelerated from rest through a potential difference of −1000 v−1000 v and (b) an el
Evgen [1.6K]

Answer:

This is the answer: The speed of a proton is about 5.0 × 10⁵ m/s

Explanation:

Because of the speeds of protons! :D

5 0
1 year ago
You just calibrated a constant volume gas thermometer. The pressure of the gas inside the thermometer is 294.0 kPa when the ther
Travka [436]

Answer: 361° C

Explanation:

Given

Initial pressure of the gas, P1 = 294 kPa

Final pressure of the gas, P2 = 500 kPa

Initial temperature of the gas, T1 = 100° C = 100 + 273 K = 373 K

Final temperature of the gas, T2 = ?

Let us assume that the gas is an ideal gas, then we use the equation below to solve

T2/T1 = P2/P1

T2 = T1 * (P2/P1)

T2 = (100 + 273) * (500 / 294)

T2 = 373 * (500 / 294)

T2 = 373 * 1.7

T2 = 634 K

T2 = 634 K - 273 K = 361° C

5 0
3 years ago
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