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Inga [223]
3 years ago
13

What basic trigonometric identity would you use to verify that sin x con x tan x= 1-cos^2x?

Mathematics
1 answer:
Blababa [14]3 years ago
7 0

Answer:

The answer is (a) ⇒ tanx = sinx/cosx

Step-by-step explanation:

∵ (sinx)(cosx)(tanx) = (sinx)(cosx)(sinx/cosx) = sin²x

∵ sin²x = 1-cos²x

∴ L.H.S = R.H.S

∴ (sinx)(cosx)(tanx) = 1 - cos²x

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4 0
3 years ago
A quantity with an initial value of 120 decays exponentially at a rate of 9.5% every 7
blondinia [14]

Answer:

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Step-by-step explanation:

6 0
3 years ago
During a flu epidemic, 44 students out of the 80 who are in Ms Grant’s class were absent. What percent were absent?
wel
44/80 x 100
=0.55 x 100
=55%
8 0
3 years ago
Read 2 more answers
What is the completely factored form of f(x)=x3+5x2+4x−6?
Gre4nikov [31]
f(x)=x^3+5x^2+4x-6
f(-3)=(-3)^3+5(-3)^2+4(-3)-6=0\implies x+3\text{ is a factor of }f(x)

Synthetic division yields

-3  |  1   5   4   -6
.    |      -3  -6    6
- - - - - - - - - - - - -
.    |  1   2  -2    0

which translates to

\dfrac{x^3+5x^2+4x-6}{x+3}=x^2+2x-2

with remainder 0. Now by the quadratic formula,

x^2+2x-2=0\implies x=\dfrac{-2\pm\sqrt{2^2-4(1)(-2)}}2=-1\pm\sqrt3

and so

f(x)=x^3+5x^2+4x-6=(x+3)(x-(-1+\sqrt3))(x-(-1-\sqrt3))
3 0
3 years ago
which order pair is a solution of the equation? y-4=7(x-6) A. only (5,4) B. only (6,5) C. both (5,4) and (6,5) D. neither​
Svet_ta [14]

Answer:

option D. Neither

Step-by-step explanation:

y-4=7(x-6)

using (5,4):

4-4=7(5-6)

0=7(-1)

0=-7

using (6,5):

5-4=7(6-6)

1=7(0)

1=0

so option D is the answer

6 0
3 years ago
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