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3 years ago

14

Reese wants to organize a party and decides to save money for it.He calculates that he needs $420 in 9 weeks.He already has $60

1 answer:

amid [387]3 years ago

3 0

Start by creating an equation. You’ll need a variable to represent what is earned per week, for example x.

So,
420=60+9x
(Since he already has 60)
Subtract the 60 from 420 to begin isolating the variable
This gives you
360=9x
Divide both sides by 9 to completely isolate the variable
This gives you
40=x
So, he needs to save up $40 each week

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divide 6 on both sides
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Let f(x)=4x^2-3 and g(x)=-x^2+2.Find f+g and state the domain. Then evaluate the sum when x=2

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f+g = 3x^2-1. domain = all real numbers. then plug in two wherever there is an x.

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Step-by-step explanation:

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4 years ago

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ElenaW [278]

<h2>Answer</h2>

$x=\sqrt{6}, y=0\\ x=-\sqrt{6} , y=0\\x=\sqrt{5} , y=-1\\x=-\sqrt{5} , y=-1$

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<h2>Explanation</h2>

Lets solve our system of equations step by step

$x^2+y^2=6$ equation (1)

$x^2-y=6$ equation (2)

1. Solve for $x^2$ in equation (2)

$x^2-y=6$

$x^2=6+y$ equation (3)

2. Replace equation (3) in equation (1) and solve for $y$

$x^2+y^2=6$

$6+y+y^2=6$

$y^2+y=0$

$y(y+1)=0$

$y=0$ or $y=-1$

3. Replace the values of $y$ in equation (3) and solve for $x$

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$x^2=6+y$

$x^2=6$

$x=\sqrt{6}$ or $x=-\sqrt{6}$

- For $y=-1$

$x^2=6+y$

$x^2=6-1$

$x^2=5$

$x=\sqrt{5}$ or $x=-\sqrt{5}$

So, the solutions of our system of equation are:

$x=\sqrt{6}, y=0\\ x=-\sqrt{6} , y=0\\x=\sqrt{5} , y=-1\\x=-\sqrt{5} , y=-1$

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