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GenaCL600 [577]
3 years ago
7

A pitcher throws a baseball that reaches the catcher in 0.75 s. The ball curves because it is spinning at an average angular vel

ocity of 230 rev/min (assumed constant) on its way to the catcher. a) Determine the angular velocity in rad/sec. b) Determine the angular displacement spend by the ball from the pitcher to the catcher.
Physics
1 answer:
7nadin3 [17]3 years ago
4 0

The change in angular displacement as a function of time is the definition given for angular velocity, this is mathematically described as

\omega = \frac{\theta}{t}

Here,

\theta = Angular displacement

t = time

The angular velocity is given as

\omega = 230rev/min

PART A) The angular velocity in SI Units will be,

\omega = 230rev/min (\frac{1min}{60s})(\frac{2\pi rad}{1rev})

\omega = \frac{23}{3}\pi rad/s \approx 24.08rad/s

PART B) From our first equation we can rearrange to find the angular displacement then

\theta = \omega t

Replacing,

\theta = (24.08)(0.75)

\theta = 18.06 rad

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A sealed 26-m3 tank is filled with 6000 moles of oxygen gas (O2) at an initial temperature of 270 K. The gas is heated to a fina
TiliK225 [7]

Answer:

The final pressure of oxygen gas is 8.33 atm.

Explanation:

From the given data

V=26 m^3 or 26000 L

T1=270K

T2=440K

n1=6000 moles

R=0.0821 L.atm/molK

Now from the ideal gas equation

P_2V_2=nRT_2\\P_2=\frac{nRT_2}{V_2}\\P_2=\frac{6000*0.0821*440}{26000}\\\\P_2=8.33 atm\\

As the options given are not defined in which unit thus the final pressure of oxygen gas is 8.33 atm.

<em>*The options are provided for a different question where </em>

3 0
4 years ago
Samaira needs to rent some tents for an outdoor family reunion in July what is the best type of tent for Samaira to rent so that
Elena L [17]

Answer:

It seems that you have missed the necessary options for us to answer this question, so I had to look for it. Anyway, here is the answer. Samaira needs to rent some tents for an outdoor family reunion in July, so the type of tent for Samaira to rent so that her family members are protected from the heat of the sun is SMOOTH and WHITE TENT. Hope this answer helps.

6 0
3 years ago
Read 2 more answers
A rod of 2.0-m length and a square (2.0 mm X 2.0 mm) cross section is made of a material with a resistivity of 6.0 E–8 Ohm meter
Alex Ar [27]

Answer:

8.33*10^-16 Watt

Explanation:

Given that

Length of the rod, l = 2 m,

Area of the rod, A = 2 x 2 mm² = 4*10^-6 m²

resistivity of the rod, p = 6*10^-8 ohm metre,

Potential difference of the rod, V = 0.5 V

Let R be the resistance of the rod, then

R = p * l / A

R = (6*10^-8 * 2) / (4*10^-6)

R = 3*10^14 ohm

Heat generated per second = V² / R Heat = (0.5)² / (3*10^14)

Heat = 0.25 / 3*10^14

Heat = 8.33*10^-16 Watt

Therefore, the rate at which heat is generated is 8.33*10^-16 Watt

4 0
4 years ago
A gas undergoes two processes. In the first, the volume remains constant at 0.170 m3 and the pressure increases from 1.50×105 Pa
Mnenie [13.5K]

Answer:

W_{T} = - 24 kJ

Explanation:

The work (W) done by the gas can be calculated using the following equation:

W = p*\Delta V = p*(V_{f} - V_{i})

<u>Where:</u>

p: is the pressure

[tex}V_{f}[/tex]: is the final volume

[tex}V_{i}[/tex]: is the initial volume

In the first process, the work done by the gas is:

W_{1} = p*\Delta V = p*0 = 0

Since the volume remains constant, the total work done by the gas is equal to zero.

In the second process, the work done by the gas is:

W_{2} = p*(V_{f} - V_{i}) = 6.00 \cdot 10^{5} Pa*(0.130 m^{3} - 0.170 m^{3}) = -24 kJ

Now, the total work done by the gas during both processes is:

W_{T} = W_{1} + W_{2} = 0 + (-24 kJ) = - 24 kJ

Therefore, the total work done by the gas during both processes is - 24 kJ.

I hope it helps you!

7 0
4 years ago
In order to change the color of light, you must change___?
Bogdan [553]
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