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3 years ago

True or false a mixture of soil has the same chemical composition throughout ?

Physics

2 answers:

choli [55]3 years ago

5 0

The. Best answer is false

myrzilka [38]3 years ago

3 0

Answer:

false

Explanation:

A mixture of soil does not have the same chemical composition through out.

at some point we begins to see different chemical composition

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What is the relationship between force in velocity selector in a bain bridge.

kifflom [539]

Answer:

In a velocity selector, there are two forces namely;

» Electric field Intensity

» Magnetic field density

Relationship:

$E _{e}= B$

E is the electric field intensity

B is the magnetic flux density

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3 years ago

g Two mirrors are touching so they have an angle of 35.4 degrees with one another. A light ray is incident on the first at an an

Mamont248 [21]

Answer:

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3 years ago

Ask Your Teacher Cam Newton of the Carolina Panthers throws a perfect football spiral at 6.9 rev/s. The radius of a pro football

faltersainse [42]

Answer:

$a=159.32\ m/s^2$

Explanation:

It is given that,

Angular speed of the football spiral, $\omega=6.9\ rev/s=43.35\ rad/s$

Radius of a pro football, r = 8.5 cm = 0.085 m

The velocity is given by :

$v=r\omega$

$v=0.085\times 43.35$

v = 3.68 m/s

The centripetal acceleration is given by :

$a=\dfrac{v^2}{r}$

$a=\dfrac{(3.68)^2}{0.085}$

$a=159.32\ m/s^2$

So, the centripetal acceleration of the laces on the football is $159.32\ m/s^2$ . Hence, this is the required solution.

6 0

3 years ago

A string under a tension of 68 N is used to whirl a rock in a horizontal circle of radius 3.7 m at a speed of 16.53 m/s. The str

alekssr [168]

Answer:

$F = 5253.7 N$

Explanation:

As we know that tension force in the string will be equal to the centripetal force on the string

so we will have

$T = \frac{mv^2}{L}$

now we have

$68 = \frac{m(16.53^2)}{3.7}$

now we have

$68 = 73.8 m$

$m = 0.92 kg$

now when string length is 0.896 m and its speed is 71.5 m/s then we will have

$F = \frac{mv^2}{r}$

$F = \frac{0.92(71.5^2)}{0.896}$

$F = 5253.7 N$

8 0

3 years ago

Read 2 more answers

Green light (λ = 518 nm) strikes a single slit at normal incidence. What width slit will produce a central maximum that is 3.00

MariettaO [177]

Answer:

6.9066 × 10⁻⁵ m

Explanation:

For constructive interference, the expression is:

$d\times sin\theta=m\times \lambda$

Where, m = 1, 2, .....

d is the distance between the slits.

The formula can be written as:

$sin\theta=\frac {\lambda}{d}\times m$ ....1

The location of the bright fringe is determined by :

$y=L\times tan\theta$

Where, L is the distance between the slit and the screen.

For small angle , $sin\theta=tan\theta$

So,

Formula becomes:

$y=L\times sin\theta$

Using 1, we get:

$y=L\times \frac {\lambda}{d}\times m$

Thus, the distance between the central maximum is 3.00 cm

First bright fringe , m = 1 occur at 3.00 / 2 = 1.50 cm

Since,

1 cm = 0.01 m

y = 0.0150 m

Given L = 2.00 m

λ = 518 nm

Since, 1 nm = 10⁻⁹ m

So,

λ = 518 × 10⁻⁹ m

Applying the formula as:

$0.0150\ m=2.00\ m\times \frac {518\times 10^{-9}\ m}{d}\times 1$

⇒ d, distance between the slits = 6.9066 × 10⁻⁵ m

7 0

3 years ago