Ask question

Ask question

All categories

3 years ago

13

If a boy (m = 50kg) at rest on skates is pushed by another boy who exerts a force of 200 N on him and if the first boy's final v

elocity is 8 m/s, what was the contact time?

2 answers:

AVprozaik [17]3 years ago

8 0

<span>F* t = (m x v_final) - (m x v_initial)

200 x t = 50x8 - 50x0

t= 50 x 8 /200

t= 2s </span>

andrew11 [14]3 years ago

8 0

The answer would be 2 seconds

You might be interested in

Help me with this! I do not understand it! I will give brainliest!<br> Is it A B C or D

Firdavs [7]

The answer is C. Click C.

3 0

3 years ago

Read 2 more answers

Look at the distance-time graph for a remote-controlled car. What is the speed of the car?

Dafna1 [17]

Speed = distance/time

Speed = 50/5
Speed = 10m/s

7 0

2 years ago

Read 2 more answers

Ixchelt burns her tongue when she takes a sip of hot coffee from her mug. Which part of this example represents heat?

bekas [8.4K]

Answer:

Explanation:

"The thermal energy moving from her coffee to the tongue" represent the heat.

Here coffee is at high temperature while tongue is at low temperature, when Ixchelt tongue make contact with coffee then thermal energy of coffee is absorbed by tongue and tongue gets burned.

As heat always from high Potential to low that is why heat is absorbed by tongue.

6 0

2 years ago

Read 2 more answers

while spinning in a centrifuge a 70.0 kg astronaut experiences an acceleration of 5.00 g, or five times the acceleration due to

ollegr [7]

Answer:

Explanation:

70.0(5.00)(9.81) = 3,433.5 = 3430 N

4 0

2 years ago

If the radius of the sun is 7.001×105 km, what is the average density of the sun in units of grams per cubic centimeter? The vol

xenn [34]

Answer:

Average density of Sun is 1.3927 $\frac{g}{cm}$ .

Given:

Radius of Sun = 7.001 × $10^{5}$ km = 7.001 × $10^{10}$ cm

Mass of Sun = 2 × $10^{30}$ kg = 2 × $10^{33}$ g

To find:

Average density of Sun = ?

Formula used:

Density of Sun = $\frac{Mass of Sun}{Volume of Sun}$

Solution:

Density of Sun is given by,

Density of Sun = $\frac{Mass of Sun}{Volume of Sun}$

Volume of Sun = $\frac{4}{3} \pi r^{3}$

Volume of Sun = $\frac{4}{3} \times 3.14 \times [7.001 \times 10^{10}]^{3}$

Volume of Sun = 1.436 × $10^{33}$ $cm^{3}$

Density of Sun = $\frac{ 2\times 10^{33} }{1.436 \times 10^{33} }$

Density of Sun = 1.3927 $\frac{g}{cm}$

Thus, Average density of Sun is 1.3927 $\frac{g}{cm}$ .

4 0

2 years ago