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GaryK [48]
3 years ago
8

Which of the following is a product formed when K reacts with Cl2?

Chemistry
2 answers:
Lera25 [3.4K]3 years ago
6 0

Answer: KCl

Explanation: Potassium [K]  has an atomic no of 19 and the electronic configuration is:

K :1s^22s^22p^63s^23p^64s^1 tends to get stable by losing one electron and forming K^+

Chlorine [Cl] has atomic no of 17 and thus the electronic configuration is :

Cl :1s^22s^22p^63s^23p^5 tends to get stable by gaining one electron and forming Cl^-

K^+ and Cl^- attract each other and form an ionic bond. As we have a chlorine molecule that is two atoms of chlorine are present, 2 atoms of potassium will react to form 2 moles of KCl.

2K+Cl_2\rightarrow 2KCl


Stels [109]3 years ago
3 0
The answer is A. 
Which is... KCI
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One

Let's start by stating what we know is wrong. Equilibrium is achieved when the reactants and products have a stable concentration. That makes D incorrect. Equilibrium is not established until about the 6th or 7th second.

The fact that you get any products at all means that the reactants will become products.  Just who is favored has to be looked at very carefully. The products start very near 0. They go up until their concentration at equilibrium. When the reach equilibrium, the products have increased to 17. The reactants have dropped from 40 to 27. By a narrow margin, I would say the products are favored.

C is incorrect. There are still reactants left.  

E is incorrect. the reactants started out with a concentration of 40. The reaction is not instantaneous.  The concentration was highest at 40 or right at the beginning. This assumes that the reactants were mixed and the products were produced and the water/liquid amount has not changed.

B is incorrect. The concentration of the reactants is higher at equilibrium.

A is wrong. It is product favored.

I'm getting none of the above.

Problem Two

AgBr is insoluble (very). You'd have to work very hard to get them to separate into their elemental form. Just putting AgBr in water isn't enough. Lots of heat and lots of electricity are needed to get the elemental form.

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3 0
3 years ago
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In the following reaction, how many grams of NaBr will produce 244 grams of NaNO3? Pb(NO3)2(aq) 2 NaBr(aq) PbBr2(s) 2 NaNO3(aq)
lyudmila [28]

Answer : The mass of NaBr is, 295.323 grams

Solution :

First we have to calculate the moles of NaNO_3.

\text{Moles of }NaNO_3=\frac{\text{Mass of }NaNO_3}{\text{Molar mass of }NaNO_3}=\frac{244g}{85g/mole}=2.87moles

Now we have to calculate the moles of NaBr.

The balanced chemical reaction is,

Pb(NO_3)_2(aq)+2NaBr(aq)\rightarrow PbBr_2(s)+2NaNO_3(aq)

From the balanced reaction we conclude that

As, 2 moles of NaNO_3 react with 2 moles of NaBr

So, 2.87 moles of NaNO_3 react with 2.87 moles of NaBr

Now we have to calculate the mass of NaBr.

\text{Mass of }NaBr=\text{Moles of }NaBr\times \text{Molar mass of }NaBr

\text{Mass of }NaBr=(2.87mole)\times (102.9g/mole)=295.323g

Therefore, the mass mass of NaBr is, 295.323 grams

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2 years ago
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Answer:

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