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GaryK [48]
4 years ago
8

Which of the following is a product formed when K reacts with Cl2?

Chemistry
2 answers:
Lera25 [3.4K]4 years ago
6 0

Answer: KCl

Explanation: Potassium [K]  has an atomic no of 19 and the electronic configuration is:

K :1s^22s^22p^63s^23p^64s^1 tends to get stable by losing one electron and forming K^+

Chlorine [Cl] has atomic no of 17 and thus the electronic configuration is :

Cl :1s^22s^22p^63s^23p^5 tends to get stable by gaining one electron and forming Cl^-

K^+ and Cl^- attract each other and form an ionic bond. As we have a chlorine molecule that is two atoms of chlorine are present, 2 atoms of potassium will react to form 2 moles of KCl.

2K+Cl_2\rightarrow 2KCl


Stels [109]4 years ago
3 0
The answer is A. 
Which is... KCI
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Because only regular-shaped objects have a consistent length, width, height, and shape.

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Because only regular-shaped objects have a consistent length, width, height, and shape. When dealing with an object composed of differing shapes, your must calculate each portion separately and then add them.

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3 years ago
A 41.1 g sample of solid CO2 (dry ice) is added to a container at a temperature of 100 K with a volume of 3.4 L. If the containe
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The pressure inside the container is 6.7 atm

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We have the ideal gas equation: P x V = n x R x T

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3 years ago
What is the total pressure exerted by the mixture of gases only products or products + reactants?
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3 0
3 years ago
A covalent chemical bond is one in which:_____.a) outer-shell electrons of one atom are transferred to the inner electron shells
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4 0
4 years ago
A pharmacy intern is asked to prepare 3 L of a 30% w/v solution. T he pharmacy stocks the active ingredient in 8-ounce bottles o
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<u>Answer:</u> The number of bottles that will be needed are 6

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This means that in 100 mL of solution, the solute present is 30 grams

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To calculate the number of bottles, we need to divide the total amount of solution needed by the amount of active ingredient present in 1 bottle, we get:

\text{Number of bottles}=\frac{\text{Amount of solution to prepare}}{\text{Amount of active ingredient in 1 bottle}}

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