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GaryK [48]
3 years ago
8

Which of the following is a product formed when K reacts with Cl2?

Chemistry
2 answers:
Lera25 [3.4K]3 years ago
6 0

Answer: KCl

Explanation: Potassium [K]  has an atomic no of 19 and the electronic configuration is:

K :1s^22s^22p^63s^23p^64s^1 tends to get stable by losing one electron and forming K^+

Chlorine [Cl] has atomic no of 17 and thus the electronic configuration is :

Cl :1s^22s^22p^63s^23p^5 tends to get stable by gaining one electron and forming Cl^-

K^+ and Cl^- attract each other and form an ionic bond. As we have a chlorine molecule that is two atoms of chlorine are present, 2 atoms of potassium will react to form 2 moles of KCl.

2K+Cl_2\rightarrow 2KCl


Stels [109]3 years ago
3 0
The answer is A. 
Which is... KCI
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6 0
2 years ago
How many moles are there in 24.00 g of NaCl
Elis [28]

Answer:

The answer to your question is 0.41 moles

Explanation:

Data

moles of NaCl = ?

mass of NaCl = 24 g

Process

To solve this problem just calculate the molar mass of NaCl, and remember that the molar mass of any substance equals to 1 mol.

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NaCl = 23 + 35.5 = 58.5 g

2.- Use proportions and cross multiplication

               58.5 g of NaCl ------------------- 1 mol

               24.0 g               ------------------- x

                     x = (24 x 1) / 58.5

                     x = 0.41 moles

6 0
3 years ago
Thallium-207 decays exponentially with a half life of 4.5 minutes. if the initial amount of the isotope was 28 grams, how many g
Agata [3.3K]
An exponential decay law has the general form: A = Ao * e ^ (-kt) =>

A/Ao = e^(-kt)

Half-life time => A/Ao = 1/2, and t = 4.5 min

=> 1/2 = e^(-k*4.5) => ln(2) = 4.5k => k = ln(2) / 4.5 ≈ 0.154

Now replace the value of k, Ao = 28g  and t = 7 min to find how many grams of Thalium-207 will remain:

A = Ao e ^ (-kt) = 28 g * e ^( -0.154 * 7) = 9.5 g

Answer 9.5 g.
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3 years ago
The reaction that is carried out by the enzyme catalase produces __________. The reaction that is carried out by the enzyme cata
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Answer:

(a) H_{2}O   (b) CO_{2}

Explanation:

The reaction that is carried out by the enzyme catalase produces H_{2} O

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