Answer:
Yes electric field between the line joining may be zero when both the charges are of opposite magnitude
Explanation:
Electric field due to a point charge is given by 
From the relation of magnitude of electric field we can see that magnitude of electric field depends upon the m,magnitude of charge and distance between them
So electric field between the line joining may be zero when both charges are of opposite magnitude ( Means if one charge is positive then other is negative )
Answer:
20m/s = 72km/h
Explanation:
change 2km=2000m
The speed of the train is
v.t=S <=> v=S/t=2000/100=20 m/s
Answer:
intensity at a point on the circle at an angle of 4.45° from the center line is 1.77 W/m².
Explanation:
See attached picture.
Answer:
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Answer:
the number of additional car lengths approximately it takes the sleepy driver to stop compared to the alert driver is 15
Explanation:
Given that;
speed of car V = 120 km/h = 33.3333 m/s
Reaction time of an alert driver = 0.8 sec
Reaction time of an alert driver = 3 sec
extra time taken by sleepy driver over an alert driver = 3 - 0.8 = 2.2 sec
now, extra distance that car will travel in case of sleepy driver will be'
S_d = V × 2.2 sec
S_d = 33.3333 m/s × 2.2 sec
S_d = 73.3333 m
hence, number of car of additional car length n will be;
n = S_n / car length
n = 73.3333 m / 5m
n = 14.666 ≈ 15
Therefore, the number of additional car lengths approximately it takes the sleepy driver to stop compared to the alert driver is 15
