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likoan [24]
3 years ago
12

The pressure at the bottom of a glass filled with water (r 5 1 000 kg/m3 ) is P. The water is poured out and the glass is filled

with ethyl alcohol (r 5 806 kg/m3 ). The pressure at the bottom of the glass is now (a) smaller than P (b) equal to P (c) larger than P (d) indeterminate.
Physics
1 answer:
bearhunter [10]3 years ago
3 0

Answer:

Option (a) is the correct answer

Explanation:

Option (a) smaller than P is the correct answer for the given question. This is because the pressure (P) at any depth 'd' from the top surface of the water with density (ρ)  is given as:

P = ρ × g × d

where,

g is the acceleration due to the gravity

thus from the above equation it can be concluded that the pressure at any depth 'd' is directly proportional to the density of the water.

thus,

in the given case the density of the water is lower than that in the first case.

Hence, the option (a) is the correct answer

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Find the acceleration of an object that has a mass of 6 kg, if it is acted upon by a net force of 42 N.
pychu [463]

Answer:

7 m/s²

Explanation:

The formula for force is:

f= m*a

We want to find acceleration, so we must rearrange the formula for a. Divide both sides of the equation by m

\frac{f}{m}=\frac{m*a}{m}

\frac{f}{m}=a

Acceleration can be found by dividing the force by the mass.

The force is 42 newtons and the mass is 6 kilograms. A newton is equal to 1 kg * m/s², therefore the force is 42 kg* m/s².

f= 42 kg*m/s^2\\m=6 kg

Substitute the values into the formula.

a=\frac{f}{m}

a=\frac{42 kg*m/s^2}{6kg}

Divide. When we divide, the kg in the numerator and denominator will cancel each other out.

a=\frac{42}{6}m/s^2

a= 7 m/s^2

The acceleration of the object is 7 meters per square seconds.

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3 years ago
How do mass and force affect the acceleration of an object?
joja [24]

Gravity affects weight, it does not affect mass. Masses always remain the same. Newton's Second Law of Motion: Force = mass x acceleration The acceleration of an object is: a) directly proportional to the net force acting on the object. ... c) inversely proportional to the mass of the object.

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3 years ago
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Coulomb's law is expressed mathematically as
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Force between two charges  = 

     ( 1/4πε₀ ) · (Charge #1) · (Charge #2) / (Distance between them)²

  in the direction away from each other.

In other words, if the force is positive, the charges are repelling.
If the force is negative, the charges are attracting.
4 0
3 years ago
You, Archimedes, suspect that the king’s crown is not solid gold but is instead gold-plated lead. To test your theory, you weigh
hjlf

Answer:

a) 16675.75 Kg/m³ b) 77.6%

Explanation:

the weight of the crown = 60 N, density of gold = 19300 Kg/m^3, density of lead = 11340 kg/m^3, density of water = 1000kg/m^3 and acceleration due to gravity = 9.8 m/s^2

upthrust on the crown = weight in air - weight when fully submerged in water = 60 - 56.4 = 3.6 N

mass of water displaced = 3.6 / 9.8  since weight = mass × g

mass of water displaced = 0.367 Kg

density of water = mass / volume

1000 = 0.367 / volume

cross multiply and find volume

volume of the crown = 0.367 / 1000 = 0.000367 m³ since the crown will displace water of equal volume according to Archimedes principle

Let V1 represent the volume of Gold and let V2 represent the volume of lead

Total volume of the crown = V1 + V2

also

density of gold = mass of gold / V1 and density of lead = mass of lead / V2

19300 = mass of gold in the crown / V1 and 11340 = mass of lead in the crown / V2

19300 V1 = mass of gold and 11340 V2 = mass of lead

add the two together

19300 V1 + 11340 V2 = weigth of the crown / 9.8

19300 V1 + 11340 V2 = 6.12 also

V1 + V2 = 0.000367

make V1 subject of the formula in equation 2

V1 = 0.000367 - V2

substitute for V1 in equation 1

19300 (0.000367 - V2) + 11340 V2 = 6.12

open the bracket

7.083 - 19300 V2 + 11340 V2 = 6.12

rearrange the equation

-7960 V2 = 6.12 - 7.083  

-7960 V2 = -0.963

V2 = -0.963 / -7960 = 0.000121 (volume of lead in the crown)

substitute V2 into equation 2

V1 + 0.000121  = 0.000367m³

V1 = 0.000367 - 0.000121 = 0.000246m³ (volume of gold in the crown)

so mass of gold in the crown = 19300 × 0.000246 = 4.748 kg

and mass of lead = 11340 × 0.000121 = 1.372 kg

average density of the crown = (mass of gold + mass of lead) / total volume = 6.12 / 0.000367 = 16675.75 kg/ m³

b) percentage make of gold = mass of gold / total mass × 100 = 77.6 % approx

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The chocolate softens and melts as it absorbs the microwaves, and it makes a mess.
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