The change in the internal energy of the ideal gas is determined as -28 J.
<h3>
Work done on the gas</h3>
The work done on the ideal gas is calculated as follows;
w = -PΔV
w = -1.5 x 10⁵(0.0006 - 0.0002)
w = -60 J
<h3>Change in the internal energy of the gas</h3>
ΔU = w + q
ΔU = -60J + 32 J
ΔU = -28 J
Thus, the change in the internal energy of the ideal gas is determined as -28 J.
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Can be numbered in 2 different ways, one box represents one element, and organized by atomic number
Answer:
Volume of water displaced = 450 - 375 = 75 ml
Vr = volume of rock = 75 ml
Wr = 9.22 - 7.60 = 1.62 N weight of 75 ml of rock
Density of rock = 1.62 N / 75 ml = .0216 N / ml
Density of water = 1000 g / 1000 ml = 9.8 N / 1000 ml = .0098 N / ml
Density of rock / density of water = .0216 / .0098 = 2.20
Answer:
0.546 ohm / μm
Explanation:
Given that :
N = 1.015 * 10^17
Electron mobility, u = 3900
Hole mobility, h = 1900
Ng = 4.42 x10^22
q = 1.6*10^-19
Resistivity = 1/qNu
Resistivsity (R) = 1/(1.6*10^-19 * 1.015 * 10^17 * 3900)
= 0.01578880889 ohm /cm
Resistivity of germanium :
R = 1 / 2q * sqrt(Ng) * sqrt(u*h)
R = 1 / 2 * 1.6*10^-19 * sqrt(4.42 x10^22) * sqrt(3900*1900)
R = 1 /0.0001831
R = 5461.4964 ohm /cm
5461.4964 / 10000
0.546 ohm / μm
Answer:
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