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eimsori [14]
3 years ago
13

The gravitational force between two objects depends on the masses and what factor between them?

Physics
1 answer:
Charra [1.4K]3 years ago
8 0
It depends on mass and distance.  
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What is momentum equal to
Margarita [4]

Answer:

mass x velocity

Explanation:

The momentum of an object is the product of its mass and velocity;

   Momentum  = mass x velocity

Mass is the quantity of matter in a body

Velocity is the rate of change of displacement with time.

Also, momentum is used to quantify the particular amount of motion a body can give.

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How far from the lens will the image of Jamie's face form?
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Approx. 983274984065823796374 meters away
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4 years ago
In a comic book, superman carries a bus (with a bomb on board) up into the air, hovers for a second and then trows the bus over
Licemer1 [7]
This breaks Newton's Second Law: For every action there is an equal and opposite reaction. The force exerted on the bus by superman should also be exerted on superman by the bus. Using the equation F=m*a, since superman's mass is so much less than the mass of the bus, he should experience a much higher acceleration than the bus does. So if the bus goes over the horizon, then superman should go MUCH further the other way. The caveat is that superman isn't able to change his density at will, which I believe is true in some storylines.
5 0
4 years ago
A car accelerates in the +x direction from rest with a constant acceleration of a1 = 1.76 m/s2 for t1 = 20 s. At that point the
alex41 [277]

Answer:

(a)v_1 = a_1t_1 = 1.76 t_1

(b) It won't hit

(c) 110 m

Explanation:

(a) the car velocity is the initial velocity (at rest so 0) plus product of acceleration and time t1

v_1 = v_0 + a_1t_1 = 0 +1.76t_1 = 1.76t_1

(b) The velocity of the car before the driver begins braking is

v_1 = 1.76*20 = 35.2m/s

The driver brakes hard and come to rest for t2 = 5s. This means the deceleration of the driver during braking process is

a_2 = \frac{\Delta v_2}{\Delta t_2} = \frac{v_2 - v_1}{t_2} = \frac{0 - 35.2}{5} = -7.04 m/s^2

We can use the following equation of motion to calculate how far the car has travel since braking to stop

s_2 = v_1t_2 + a_2t_2^2/2

s_2 = 35.2*5 - 7.04*5^2/2 = 88 m

Also the distance from start to where the driver starts braking is

s_1 = a_1t_1^2/2 = 1.76*20^2/2 = 352

So the total distance from rest to stop is 352 + 88 = 440 m < 550 m so the car won't hit the limb

(c) The distance from the limb to where the car stops is 550 - 440 = 110 m

8 0
3 years ago
Uuse Lenz's law to explore what happens when an electromagnet is activated a short distance from a wire loop. You will need to u
Alex777 [14]

Answer:

Explanation:

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According to the Lenz's law, the direction of induced emf is such that it always opposes the cause due to which it is produced.

4 0
3 years ago
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