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3 years ago

How do convection cells in Earth's atmosphere cause high and low pressure belts?

Physics

1 answer:

seropon [69]3 years ago

6 0

Areas of rising air causes low air pressure areas and <span>Areas of sinking air are areas of high air </span>pressure

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Some good estimates about the human body can be made if it is assumed that we are made mostly of water. The mass of a water mole

Bezzdna [24]

Answer:

Explanation:

Given

mass of water molecule $m=2.99\times 10^{-26}\ kg$

mass of person $M=62\ kg$

It is given that body is mostly made up of water

suppose n water molecules constitutes 62 kg

so $n\times m=M$

$n=\frac{62}{2.99\times 10^{-26}}$

$n=20.73\times 10^{26}\ kg$

6 0

3 years ago

A rigid, nonconducting tank with a volume of 4 m3 is divided into two unequal parts by a thin membrane. One side of the membrane

kondor19780726 [428]

The final temperature of the system will be equal to the initial temperature, and which is 373K. The work done by the system is 409.8R Joules.

To find the answer, we need to know about the thermodynamic processes.

<h3>How to find the final temperature of the gas?</h3>

Any processes which produce change in the thermodynamic coordinates of a system is called thermodynamic processes.
In the question, it is given that, the tank is rigid and non-conducting, thus, dQ=0.
The membrane is raptured without applying any external force, thus, dW=0.
We have the first law of thermodynamic expression as,

$dU=dQ-dW$

Here it is zero.

$dU=0$ ,

As we know that,

$dU=C_pdT=0\\\\thus, dT=0\\\\or , T=constant\\\\i.e, T_1=T_2$

Thus, the final temperature of the system will be equal to the initial temperature,

$T_1=T_2=100^0C=373K$

We found that the process is isothermal,
Thus, the work done will be,

$W=RT*ln(\frac{V_2}{V_1} )=373R*ln(\frac{4}{\frac{4}{3} })\\ \\W=409.8R J$

Where, R is the universal gas constant.

<h3>What is a reversible process?</h3>

Any process which can be made to proceed in the reverse direction is called reversible process.
During which, the system passes through exactly the same states as in the direct process.

Thus, we can conclude that, the final temperature of the system will be equal to the initial temperature, and which is 373K. The work done by the system is 409.8R Joules.

Learn more about thermodynamic processes here:

brainly.com/question/28067625

#SPJ1

7 0

2 years ago

Read 2 more answers

a group of students is asking people whether they use plastic bags. what are the students doing? a. stating a problem b. analyzi

notsponge [240]

I believe the correct answer from the choices listed above is option C. A group of students is asking people whether they use plastic bags. By doing such, the students are <span>collecting data. They are collecting data of how many people uses plastic bags. Hope this answers the question.</span>

6 0

3 years ago

Read 2 more answers

I don't understand help

Bumek [7]

Answer:

Pe is stored energy to do work Pe is stored in objects that are at rest

KE defined as the energy of motion

began to move

Not sure about the rest

hope this helps

Explanation:

6 0

2 years ago

1. A piece of metal weighs 50.0 N in air, 36.0 N in water, and 41.0 N in an unknown

denis23 [38]

Answer:

a) 3.37 x $10^{3} kg/m^3$

b) 6.42kg/ $m^{3}$

Explanation:

a) Firstly we would calculate the volume of the metal using it`s weight in air and water , after finding the weight we would find the density .

Weight of metal in air = 50N = mg implies the mass of metal is 5kg.

Now the difference of weight of the metal in air and water = upthrust acting on it = volume (metal) p (liquid) g = V (1000)(10) = 14N. So volume of metal piece = 14 x $10^{-4}$ $kg/m^{3}$ . So density of metal = mass of metal / volume of metal = 5 / 14 x $10^{-4}$ $kg/m^{3}$ = 3.37 x $10^{3} kg/m^3$

b) Water exerts a buoyant force to the metal which is 50−36 = 14N, which equals the weight of water displaced. The mass of water displaced is 14/10 = 1.4kg Since the density of water is 1kg/L, the volume displaced is 1.4L. Hence, we end up with 3.57kg/l. Moreover, the unknown liquid exerts a buoyant force of 9N. So the density of this liquid is 6.42kg/ $m^{3}$

3 0

3 years ago