A rocket ship is accelerated by the SRB and the main engines for 2.0 minutes and the main engines for 8.5 minutes after the launch. The acceleration of the ship during the first 2.0 minutes is 11 m/s² (D).
A rocket ship has several engines and thrusters. We can divide its initial movement into 2 parts:
- From t = 0 min to t = 2.0 min, the SRB and the main engines act together and the speed goes from 0 m/s (rest) to 1341 m/s.
- From t = 2.0 min to t = 8.5 min, the main engines alone accelerate the ship form 1341 m/s to 7600 m/s.
We want to know the acceleration in the first part (first 2.0 minutes). We need to consider that:
- The speed increases from 0 m/s to 1341 m/s.
- The time elpased is 2.0 min.
- 1 min = 60 s.
The acceleration of the ship during the first 2.0 minutes is:
A rocket ship is accelerated by the SRB and the main engines for 2.0 minutes and the main engines for 8.5 minutes after the launch. The acceleration of the ship during the first 2.0 minutes is 11 m/s² (D).
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Answer:
The minimum force to start the block moving up the wall = 49 N
Explanation:
Friction: This is the force that tend to oppose the motion of two bodies in contact. The S.I unit of frictional force is Newton (N)
The minimum force required to start the block moving up the wall = Frictional Force.
I.e F = Frictional force.
And, F = μR..........................Equation 1
Where μ = coefficient of static friction, R = Normal reaction.
But R = mg ( on a level surface).................. Equation 2
Where m = mass, g = acceleration due to gravity.
Given: m = 10 kg,
Constant: g = 9.8 m/s²
substituting these values into Equation 2
R = 10 × 9.8
R = 98 N.
Also given: μ = 0.50
Substituting these values into equation 1
F = 98 × 0.5
F = 49 N.
Therefore The minimum force to start the block moving up the wall = 49 N
Answer:
(D ) 
and 
Explanation:
Given that, the rms value of current is 10 ampere and its frequency is 50 Hz.
Now maximum value of current can be calculated as,
The time period is defined as,
Now the time taken by alternating current going from zero to maximum value is,
Therefore, the time taken by alternating current to reach maximum value is 
and the peak value of current is .
