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3 years ago

How many weeks does it take for one full moon to go to the next full moon

Chemistry

2 answers:

OlgaM077 [116]3 years ago

8 0

4 weeks for the moon to go to the next full moon

9966 [12]3 years ago

6 0

It takes two weeks. the person below was wrong

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What is the lewis dot structure of NaBr

Anon25 [30]

LiF, LiCl, LiBr, LiI, LiAtNaF, NaCl, NaBr, NaI, NaAtKF, KCl, KBr, KI, KAtRbF, RbCl, RbBr, RbI, RbAt CsF, CsCl, CsBr, CsI, CsAt FrF, FrCl, FrBr, FrI, FrAt

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2 years ago

What is the top of a transverse wave

Andru [333]

It would be called the crest.

Happy to help! Have a great evening.

~Brooke❤️

8 0

3 years ago

How does Hanukkah relate to science?

kkurt [141]

Answer:

oil = burn for 8 days = absurd = doesnt make sense but it happened lol

Explanation:

4 0

2 years ago

What is the answer please

xeze [42]

Answer:

Selenium

Explanation:

Oxygen is present in the group sixteen.

This group consist of oxygen, sulfur, selenium, tellurium and polonium.

All of these have same number of valance electrons thus they show similar properties.

From the given list of elements only selenium is belong to oxygen family thus it has properties similar to the oxygen.

Electronic configuration of oxygen:

O = [He] 2s² 2p⁴

Electronic configuration of selenium:

Se = [Ar] 3d¹⁰ 4s² 4p⁴

While aluminium, boron and phosphorus are belongs to other groups that's why their properties are not similar to the phosphorus.

phosphorus is present in group 15.

Boron and aluminium are present in group 13.

6 0

3 years ago

Object A specific heat is 2.45 J/g C and object B specific heat is 0.82 J/g C. Which object will heat up more if they have the s

Artist 52 [7]

Answer: Object B will heat up more.

Explanation:

The formula for specific heat is as follows.

Q = $m C \Delta T$

Where,

Q = heat provided

m = mass

C = specific heat

$\Delta T$ = change in temperature

Now, both the objects have same mass and equal amount of heat is applied.

According to the formula, the equation will be as follows.

$Q_{1}$ = $Q_{2}$

$m C_{1}\Delta T$ = $m C_{2}\Delta T_{2}$

Cancel m from both sides, as mass is same. Therefore,

$C_{1} (T_{f} - T_{i})_A$ = $C_{2}(T_{f} - T_{i})_B$

Cancel out the initial temperature and put the values of specific heat, then the equation will be as follows.

$2.45 (T_{f})_A$ = $0.82(T_{f})_B$

Therefore, from the above equation it can be concluded that the object with low specific heat will heat up more as its specific heat will be inversely proportional to its final temperature.

Hence, object B will heat up more.

4 0

2 years ago