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statuscvo [17]
4 years ago
6

Please answer correctly..will give the brainliest!Urgent!!!!!!​

Chemistry
1 answer:
vladimir2022 [97]4 years ago
7 0
The answer for dry sample of carbon dioxide is upwards into a gas jar
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The pH of pure water is 7.
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Choose one region on the world map. How does the climate there differ during El Niño and La Niña?
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Temperatures in the central pacific ocean are warmer than usual and there is less rainfall.            hope this helps! :)
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3 years ago
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__Zn + __HCl --> __ZnCl2 + __H2
mylen [45]

Answer:

1. The balanced equation:

Zn + 2HCl —> ZnCl₂ + H₂

The coefficients are: 1, 2, 1, 1

2. 2.34 moles of HCl

Explanation:

1. The balanced equation

__Zn + __HCl —> __ZnCl₂ + __H₂

There are 2 atoms of H on the right side and 1 atom on the left side

It can be balance by writing 2 before HCl as shown below:

Zn + 2HCl —> ZnCl₂ + H₂

Now the equation is balanced.

The coefficients are: 1, 2, 1, 1

2. Determination of the number of mole of HCl that reacted.

NOTE: 1 mole of H₂ = 22.4 L at STP.

Zn + 2HCl —> ZnCl₂ + H₂

From the balanced equation above,

2 moles of HCl reacted to produce 1 mole (i.e 22.4 L) of H₂.

Finally, we shall determine the number of mole of HCl needed to produce 26.22 L of H₂. This can be obtained as follow:

From the balanced equation above,

2 moles of HCl reacted to produce 22.4 L of H₂.

Therefore, Xmol of HCl will react to produce 26.22 L of H₂ i.e

Xmol of HCl = (2 × 26.22)/22.4

Xmol of HCl = 2.34 moles

Thus, 2.34 moles of HCl is needed for the reaction.

5 0
3 years ago
Determine the empirical and molecular formula for chrysotile asbestos. Chrysotile has the following percent composition: 28.03%
nlexa [21]

<u>Answer:</u> The empirical and molecular formula of chrysotile is Mg_3Si_2H_3O_4 and Mg_6Si_4H_6O_{16}

<u>Explanation:</u>

We are given:

Percentage of Mg = 28.03 %

Percentage of Si = 21.60 %

Percentage of H = 1.16 %

Percentage of O = 49.21 %

Let the mass of compound be 100 g. So, percentages given are taken as mass.

Mass of Mg = 28.03 g

Mass of Si = 21.60 g

Mass of H = 1.16 g

Mass of O = 49.21 g

To formulate the empirical formula, we need to follow some steps:

  • <u>Step 1:</u> Converting the given masses into moles.

Moles of Magnesium = \frac{\text{Given mass of Magnesium}}{\text{Molar mass of Magnesium}}=\frac{28.03g}{24g/mole}=1.17moles

Moles of Silicon = \frac{\text{Given mass of Silicon}}{\text{Molar mass of Silicon}}=\frac{21.06g}{28g/mole}=0.752moles

Moles of Hydrogen = \frac{\text{Given mass of Hydrogen}}{\text{Molar mass of Hydrogen}}=\frac{1.16g}{1g/mole}=1.16moles

Moles of Oxygen = \frac{\text{Given mass of oxygen}}{\text{Molar mass of oxygen}}=\frac{49.21g}{16g/mole}=3.07moles

  • <u>Step 2:</u> Calculating the mole ratio of the given elements.

For the mole ratio, we divide each value of the moles by the smallest number of moles calculated which is 0.752 moles.

For Magnesium = \frac{1.17}{0.752}=1.5

For Silicon = \frac{0.752}{0.752}=1

For Hydrogen = \frac{1.16}{0.752}=1.5

For Oxygen = \frac{3.07}{0.485}=4.08\approx 4

To convert the mole ratios into whole numbers, we multiply individual mole ratios by 2

Mole ratio of Magnesium = (2 × 1.5) = 3

Mole ratio of Silicon = (2 × 1) = 2

Mole ratio of Hydrogen = (2 × 1.5) = 3

Mole ratio of Oxygen = (2 × 4) = 8

  • <u>Step 3:</u> Taking the mole ratio as their subscripts.

The ratio of Mg : Si : H : O = 3 : 2 : 3 : 8

The empirical formula for the given compound is Mg_3Si_2H_3O_8

For determining the molecular formula, we need to determine the valency which is multiplied by each element to get the molecular formula.

The equation used to calculate the valency is :

n=\frac{\text{Molecular mass}}{\text{Empirical mass}}

We are given:

Mass of molecular formula = 520.8 g/mol

Mass of empirical formula = [(24 × 3) + (28 × 2) + (1 × 3) + (16 × 8)] = 259 g/mol

Putting values in above equation, we get:

n=\frac{520.8g/mol}{259g/mol}=2

Multiplying this valency by the subscript of every element of empirical formula, we get:

Mg_{(3\times 2)}Si_{(2\times 2)}H_{(3\times 2)}O_{(8\times 2)}=Mg_6Si_4H_6O_{16}

Hence, the empirical and molecular formula of chrysotile is Mg_3Si_2H_3O_4 and Mg_6Si_4H_6O_{16}

5 0
4 years ago
Which of the following elements has the largest atomic radius
Olin [163]

Answer: Calcium

Explanation:

not 100% sure but i looked it up and got calcium. 99% sure.

8 0
3 years ago
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