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Ierofanga [76]
4 years ago
10

Molecules that have the same chemical formula (same numbers of each atom) but different three-dimensional shapes are called ____

_. molecules that have the same chemical formula (same numbers of each atom) but different three-dimensional shapes are called _____. functional groups isotopes hydrocarbons isomers enantiomers
Chemistry
2 answers:
4vir4ik [10]4 years ago
4 0

Answer : The correct option is, Isomers

Explanation :

Isotope : It is defined as the element that have the same number of protons but have the different number of neutrons of each of the atom.

Functional groups : It is defined as they are specific grouping of atoms within the molecule that have their own characteristic properties.

For examples : alcohols, amines, carboxylic acids, ketones, ethers etc.

Hydrocarbons : It is defined as the type of organic compound that contains only hydrogen and the carbon atoms.

Enantiomers : When the two stereoisomers differ only in their arrangement of atoms and groups in space and exhibit non-superimposable object mirror image relationship.

Isomer : It is defined as a molecule have the same molecular or chemical formula but the different chemical structure or shape.

For example :

There are three structural isomers of n-hexene that is based on the location of the double-bonded carbon atoms with the other atoms.

In n-hexane, 'n' shows that the chain should be straight chain there is no branching.

The three structural isomers of n-hexene are, 1-hexene, 2-hexene and 3-hexene.

Hence, the correct option is, Isomers

katen-ka-za [31]4 years ago
3 0

The given blank can be filled with isomers.  

The isomers in chemistry refers to the molecules or ions with similar formulas, but different compositions. The isomers refer to the molecules that exhibit the same chemical formula, however, distinct three-dimensional shapes. Though isomers do not always share identical properties. The two prime forms of isomerism are stereoisomerism or spatial isomerism and structural isomerism or constitutional isomerism.  


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If I titrate an acid with 255mL of 3.4 M NaOH (base) and reach the equivalence point, how many moles of H+ ions were in the acid
FromTheMoon [43]

Answer:

Molar Concentration = \frac{Moles of Solute}{Litres of Solution}

                                     = \frac{3.4}{0.255}

                                    =  13.33

No. of H+ ions present = 13.33

pH value = - log[13.33]

               =  -1.12

Explanation:

The equivalence point, or stoichiometric point, of a substance response is the point at which synthetically identical amounts of reactants have been blended. As such, the moles of corrosive are equal to the moles of base, as per the condition (this doesn't really infer a 1:1 molar proportion of acid:base, simply that the proportion is equivalent to in the condition). It tends to be found by methods for a marker, for instance phenolphthalein or methyl orange. The endpoint (identified with, however not equivalent to the equivalence point) alludes to the point at which the marker changes shading in a colorimetric titration.

7 0
3 years ago
How many liters of fluorine gas, at standard temperature and pressure, will react with 23.5 grams of potassium metal?
ArbitrLikvidat [17]
The balanced chemical reaction is written as:

<span>2K + F2 ---> 2 KF

We are given the amount of potassium metal to be used in the reaction. This will be the starting point for the calculation. We do as follows:

23.5 g K ( 1 mol / 39.1 g ) ( 1 mol F2/2 mol K ) ( 22.4 L / 1 mol ) = 13.46 L F2 

</span>
8 0
3 years ago
A weak monoprotic acid is titrated with 0.100 MNaOH. It requires 50.0 mL of the NaOH solution to reach the equivalence point. Af
larisa86 [58]

Explanation:

The given reaction is as follows.

        HA(aq) + NaOH (aq) \rightleftharpoons NaA(aq) + H_{2}O(l)

Hence, number of moles of NaOH are as follows.

        n = 0.05 L \times 0.1 M

           = 0.005 mol

After the addition of 25 ml of base, the pH of a solution is 3.62. Hence, moles of NaOH is 25 ml base are as follows.

             n = 0.025 L \times 0.1 M

                = 0.0025 mol

According to ICE table,

         HA(aq) + NaOH (aq) \rightleftharpoons NaA(aq) + H_{2}O(l)

Initial:     0.005 mol   0.0025 mol              0                  0

Change: -0.0025 mol  -0.0025 mol        +0.0025 mol

Equibm:   0.0025 mol    0                         0.0025 mol

Hence, concentrations of HA and NaA are calculated as follows.

          [HA] = \frac{0.0025 mol}{V}

        [NaA] = \frac{0.0025 mol}{V}

       [A^{-}] = [NaA] = \frac{0.0025 mol}{V}

Now, we will calculate the pK_{a} value as follows.

          pH = pK_{a} + log \frac{A^{-}}{HA}

       pK_{a} = pH - log \frac{[A^{-}]}{[HA]}

                  = 3.42 - log \frac{\frac{0.0025 mol}{V}}{\frac{0.0025}{V}}

                  = 3.42

Thus, we can conclude that pK_{a} of the weak acid is 3.42.

           

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3.0
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6 0
3 years ago
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