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vovangra [49]
3 years ago
9

The parallelogram has the angle measures shown. Can you conclude that it is a rhombus, a

Mathematics
1 answer:
Masja [62]3 years ago
6 0

The given parallelogram is a rhombus

Solution:

Option A: Rhombus

Let us recall the property of rhombus.

  • Diagonals bisect each other at right angles.
  • Opposite angles are congruent.

Here diagonals bisect the angles equally each 72°.

Opposite angles are congruent(72° + 72° = 144°).

Hence the given parallelogram is a rhombus.

Option B: Rectangle

Let us recall the property of rectangle.

  • Diagonals bisect each other.
  • All the angles of a rectangle are 90°.

Here 72° + 72° = 144°, not 90°.

So, the given parallelogram is not a rectangle.

Option C: Square

Let us recall the property of square.

  • Diagonals bisect each other.
  • All the angles of a square are 90°.

Here 72° + 72° = 144°, not 90°.

So, the given parallelogram is not a square.

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