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vovangra [49]
3 years ago
9

The parallelogram has the angle measures shown. Can you conclude that it is a rhombus, a

Mathematics
1 answer:
Masja [62]3 years ago
6 0

The given parallelogram is a rhombus

Solution:

Option A: Rhombus

Let us recall the property of rhombus.

  • Diagonals bisect each other at right angles.
  • Opposite angles are congruent.

Here diagonals bisect the angles equally each 72°.

Opposite angles are congruent(72° + 72° = 144°).

Hence the given parallelogram is a rhombus.

Option B: Rectangle

Let us recall the property of rectangle.

  • Diagonals bisect each other.
  • All the angles of a rectangle are 90°.

Here 72° + 72° = 144°, not 90°.

So, the given parallelogram is not a rectangle.

Option C: Square

Let us recall the property of square.

  • Diagonals bisect each other.
  • All the angles of a square are 90°.

Here 72° + 72° = 144°, not 90°.

So, the given parallelogram is not a square.

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---------------------------------------------------------------------------------------

Work Shown:

The triangles are similar to each other due to the AA (angle angle) postulate. The top angles are overlapping or shared angles. So that's the first pair. The second pair of angles is either bottom pair of angles, from the fact that corresponding angles are congruent. This is only true if the lines are parallel.

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