Answer:
The probability of eating pizza given that a new car is bought is 0.952
Step-by-step explanation:
This kind of problem can be solved using Baye’s theorem of conditional probability.
Let A be the event of eating pizza( same as buying pizza)
while B is the event of buying a new car
P(A) = 34% = 0.34
P(B) = 15% = 15/100 = 0.15
P(B|A) = 42% = 0.42
P(B|A) = P(BnA)/P(A)
0.42 = P(BnA)/0.34
P(B n A) = 0.34 * 0.42 = 0.1428
Now, we want to calculate P(A|B)
Mathematically;
P(A|B = P(A n B)/P(B)
Kindly know that P(A n B) = P(B n A) = 0.1428
So P(A|B) = 0.1428/0.15
P(A|B) = 0.952
Answer:
Your que. isn't very clear. Should there be a graph or diagram? Please confirm
Answer:
10
Step-by-step explanation:
Hope it helps! :D
Setup Fee= $5,500Per CD Charge= $1.00Desired Cost Per CD= $3.50
x= number of CDs
Desired Cost Per CD= Cost per CD + Setup Fee
($3.50 * x)= ($1.00 * x) + $5,500multiply inside parentheses
$3.50x= $1.00x + $5,500subtract $1.00x from both sides
$2.50x= $5,500divide both sides by $2.50
x= 2,200 CDs
ANSWER: x= 2,200 CDs
Hope this helps! :)
Analyzing the given values and the given equation, we have the following:
A = $25,000
r = 0.11
t = 6
The equation has the form:
y = A (1-r)^t
Plugging in the given values into the equation,
y = $25,000 (1 - 0.11)^6
y = $25,000 (0.89)^6
Therefore, the answer is
A. y=25,000(.89)^6
