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Vikentia [17]
3 years ago
8

What happens to the velocity of a sound wave in air if the temperature of the air increases? A. velocity increases B. velocity d

oes not change C. velocity decreases D. velocity drops to zero
Physics
2 answers:
Drupady [299]3 years ago
5 0

Answer:

Velocity increases for plato users

Explanation:

tigry1 [53]3 years ago
3 0
The answer of your question is A.
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9. The three types of stress that act on Earth's rocks are compression, tension, and A. strain. B. shear. C. tephra. D. shale.
Evgen [1.6K]
<span>The three main types of stress in a rock are shearing, tension, and compression. hope. that helped</span>
5 0
3 years ago
Read 2 more answers
A horizontal force of 750 N is needed to overcome the force of static friction between a level floor and a 250-kg crate. If g-9.
seraphim [82]

Answer:

0.31

Explanation:

horizontal force, F = 750 N

mass of crate, m = 250 kg

g = 9.8 m/s^2

The friction force becomes applied force = 750 N

According to the laws of friction,

Friction force = μ x Normal reaction of the surface

here, μ be the coefficient of friction

750 = μ x m g

750 = μ x 250 x 9.8

μ = 0.31

Thus, the coefficient of static friction is 0.31.

7 0
3 years ago
A car, traveling at , encounters a dip in the road. The radius of curvature at the bottom of the dip is . Each of the car’s four
labwork [276]

Answer:

spring deflection is  x = (v2 / R + g) m / 4

Explanation:

We will solve this problem with Newton's second law. Let's analyze the situation the car goes down a road and finds a dip (hollow) that we will assume that it has a circular shape in the lower part has the car weight, elastic force and a centripetal acceleration

 

Let's write the equations on the Y axis of this description

       Fe - W = m a_{c}

Where Fe is elastic force, W the weight and a_{c}  the centripetal acceleration. The elastic force equation is

       Fe = - k x

     

       4 (k x) - mg = m v² / R

The four is because there are four springs, R is theradio of dip

We can calculate the deflection (x) of the springs

       x = (m v2 / R + mg) / 4

       

       x = (v2 / R + g) m / 4

5 0
3 years ago
A uniform brick of length 21 m is placed over
Paha777 [63]

Answer:

15.75 m

Explanation:

First, let's look at the top brick by itself.  In order for it not to tip over the bottom brick, its center of gravity must be right at the edge of the bottom brick.  So the edge of the top brick must be 10.5 m from the edge of the bottom brick.

Now let's look at both bricks as a combined mass.  We know the total length of this combined brick is 10.5 m + 21 m = 31.5 m.  And we know that for it to not tip over the edge of the surface, its center of gravity must be at the edge.  So the edge of the combined brick must be 31.5 m / 2 = 15.75 m from the edge of the surface.

6 0
4 years ago
The 1.5kg ball is launched straight upward with an initial velocity of 7m/s. What is the maximum height it will reach?​
Temka [501]

Answer:

h = 2.5 m

Explanation:

Given that,

Mass of a ball, m = 1.5 kg

Initial velocity of the ball, u = 7 m/s

We need to find the maximum height reached by the ball. Let it is be h. Using the conservation of energy to find it such that,

mgh=\dfrac{1}{2}mu^2\\\\h=\dfrac{u^2}{2g}

Put all the values,

h=\dfrac{7^2}{2\times 9.8}\\\\=2.5\ m

So, it will reach to a height of 2.5 m.

8 0
3 years ago
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