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Katena32 [7]
3 years ago
12

The amount of WORK done is determined by 2 factors.

Physics
1 answer:
RUDIKE [14]3 years ago
6 0

Explanation :

Work is done when a force is applied to create a displacement on an object.

Thus, the work done depends on the two factors i.e.

(1) Applied force (F)

(2) Distance or displacement (d)

Mathematically, work done is W= F.s

It also depends on the angle between the force and the displacement.

        W=Fs\ cos\ \theta

For example,

A person carries a weight of 20 kg and lifts it on his head 1.5 m above the surface. So, the work done by him on the luggage will be:

W= F\times s

or

W=m\times g \times s

W=20\ kg\times 9.8\ m/s^2\times 1.5\ m

So, W=294\ Joules

Hence, the work done by him on the luggage is 294 Joules.

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Answer:

Impedance = 93.75 ohms

Current = 1.81 A

Explanation:

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Inductance = L = 0.2 H

Inductive reactance = XL = X_{L}= = ωL = (2πf) L

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Capacitive reactance = 1 / ωC = 1/(2πf)C = 1 / [(2π)(60)(0.1 × 10⁻3)]

= 26.526 Ohms  

Impedance = Z = \sqrt{R^{2} + (X_{L} - X_{C})^{^{2}}} =

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3 years ago
2. Tony sets up an experiment inside his classroom. He spaces 5 plants at equal
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a

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Use Newton’s Universal Law of Gravitation to calculate the magnitude of the gravitational force between a 200 kg refrigerator an
expeople1 [14]

Answer:

3.735×10⁻⁶ N

Explanation:

From newton' s law of universal gravitation,

F = Gmm'/r² .............................. Equation 1

Where F = Gravitational force between the person and the refrigerator, m = mass of the person, m' = mass of the refrigerator, r = distance between the person and the refrigerator. G = gravitational universal constant.

Given: m = 70 kg, m' = 200 kg, r = 0.5 m

Constant: G = 6.67×10⁻¹¹ Nm²/kg².

F = (6.67×10⁻¹¹×70×200)/0.5²

F = 93380×10⁻¹¹/0.25

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The record for the highest speed achieved in alaboratory for a
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0.000234 seconds

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Since the row is 0.15m, its radius of rotation must be 0.15 / 2 = 0.075 m

We can start by calculating the angular speed of the rod:

\omega = \frac{v}{r} = \frac{2010}{0.075} = 26800 rad/s

Since one revolution equals to 2π rad. The speed in revolution per second must be

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The number of seconds per revolution, or period, is the inverse:

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Is the frictional force the same as the applied force when the net force equals zero?
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Since the net force is to the right (in the direction of the applied force), then the applied force must be greater than the friction force. The friction force can be determined using an understanding of net force as the vector sum of all the forces.

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