Both the technician are correct.
All the driving force in the universe always flow from the higher body to lower body, until unless acted by external forces. Which means heat always flow from a hotter body to colder body, high pressure always flow to low pressure.
Therefore the both the technician are correct.
Explanation:
It is given that,
Frequency of vibration, f = 215 Hz
Amplitude, A = 0.832 mm
(a) Let T is the period of this motion. It is given by the following relation as :
![T=\dfrac{1}{f}](https://tex.z-dn.net/?f=T%3D%5Cdfrac%7B1%7D%7Bf%7D)
![T=\dfrac{1}{215}](https://tex.z-dn.net/?f=T%3D%5Cdfrac%7B1%7D%7B215%7D)
![T=4.65\times 10^{-3}\ s](https://tex.z-dn.net/?f=T%3D4.65%5Ctimes%2010%5E%7B-3%7D%5C%20s)
(b) Speed of sound in air, v = 343 m/s
It can be given by :
![v=f\times \lambda](https://tex.z-dn.net/?f=v%3Df%5Ctimes%20%5Clambda)
![\lambda=\dfrac{v}{f}](https://tex.z-dn.net/?f=%5Clambda%3D%5Cdfrac%7Bv%7D%7Bf%7D)
![\lambda=\dfrac{343\ m/s}{215\ Hz}](https://tex.z-dn.net/?f=%5Clambda%3D%5Cdfrac%7B343%5C%20m%2Fs%7D%7B215%5C%20Hz%7D)
![\lambda=1.59\ m](https://tex.z-dn.net/?f=%5Clambda%3D1.59%5C%20m)
Hence, this is the required solution.
Answer:
Facilitated diffusion and active transport both utilize proteins to transport substances across membranes. Differences between active transport and facilitated diffusion 1. Active transport requires an input of energy, usually ATP, while facilitated transport does not.
The magnitude of the average acceleration of the ball during this time interval will be 1969.69 m/s².
<h3>What is acceleration?</h3>
The rate of velocity change concerning time is known as acceleration.
Given data;
Initial velocity, u= 27.5 m/s
Rebound velocity, v= 21.0 m/s
Time elapsed, t = 3.30 × 10⁻³ seconds.
To find ;
Average acceleration, a
The average acceleration when the change in velocity is observed by the formula as:
![\rm a_{avg}= \frac{v-u}{t}](https://tex.z-dn.net/?f=%5Crm%20a_%7Bavg%7D%3D%20%5Cfrac%7Bv-u%7D%7Bt%7D)
Substitute the given values:
![\rm a_{avg}= \frac{27.5-21.0}{3.30 \times 10^{-3}} \\\\ a_{avg}= 1969.69 \ m/s^2](https://tex.z-dn.net/?f=%5Crm%20a_%7Bavg%7D%3D%20%5Cfrac%7B27.5-21.0%7D%7B3.30%20%5Ctimes%2010%5E%7B-3%7D%7D%20%20%5C%5C%5C%5C%20a_%7Bavg%7D%3D%201969.69%20%20%5C%20m%2Fs%5E2)
Hence, the magnitude of the average acceleration of the ball during this time interval will be 1969.69 m/s².
To learn more about acceleration, refer to the link brainly.com/question/2437624#SPJ1.
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Answer:
4
Explanation:
there are 4 complete wavelengths