Number 11
Since the auditorium can hold 600 and the student body will be divide by four parts
The answer is
x ≤ 2400
Answer:
d
Step-by-step explanation:
A. 2x + 3y = −6
B. 3x − 2y = 6
C. 3x − 2y = 12
D. 2x − 3y = 18
$=(a^2-10a)-(b^2+6b) +16$
$=[(a^2-2(5)a+25)-25]-[(b^2+2(3)b+9)-9]+16$
$=(a-5)^2-25-(b+3)^2+9+16$
$=(a-5)^2-(b+3)^2$
Answer:
2m/s² ; - 2m/s²
25m ; 50m ; 25m
6.67 m/s²
Step-by-step explanation:
The acceleration and deceleration :
Both rates are the Same from the graph ;
According to scenario described, acceleration = 2m/s²
Deceleration occurred in equal time interval = - 2m/s
Distance covered during each stage:
Stage 1 : area of triangle
0.5 * base * height
0.5 * 5 * 10 =25 m
Stage 2: area of rectangle :
Length * breadth = 5 * 10 = 50 m
Stage 3 : area of triangle
0.5 * base * height
0.5 * 5 * 10 =25 m
Average Velocity :
Total distance / time = (25 + 50 + 25) / 15 = 100/ 15 = 6. 67 m/s
9514 1404 393
Answer:
(A) one solution: x = 3
(B) one solution: x = -10
(C) one solution: x = 4
Step-by-step explanation:
An equation will have one solution if it can be reduced to the form ...
ax +b = 0
It will have an infinite number of solutions if it reduces to the form ...
0 = 0
It will have no solution if it reduces to the form ...
1 = 0
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<h3>(A)</h3>
2x + 4 (x - 1) = 2 + 4x . . . . . . given
Subtract 2 +4x from both sides and simplify
2x -6 = 0 . . . . . . . . . . . . . . one solution (x=3)
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<h3>(B)</h3>
25 - x = 15 - (3x + 10)
Add 3x -5 to both sides and simplify
2x +20 = 0 . . . . . . . . . . . one solution (x=-10)
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<h3>(C)</h3>
4x = 2x + 2x + 5 (x - 4)
Subtract 4x from both sides and simplify
0 = 5x -20 . . . . . . . . . . one solution (x=4)
