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Dahasolnce [82]
3 years ago
11

12=x÷8 I need help please

Mathematics
2 answers:
scoray [572]3 years ago
8 0
X=96
I believe that’s the answer
Simora [160]3 years ago
3 0

Answer:

x=96

Step-by-step explanation:

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Write the explicit form of the arithmetic sequence shown below:<br> -4, 3, 10, ...
Vinil7 [7]

Answer:

17

Step-by-step explanation:

_4 to +3 = 7

3 to 10 =7

thus the sequence is 7

the answer is 10+7=17

7 0
3 years ago
Prove the polynomial identity.
Kaylis [27]

Answer:

Proven

Step-by-step explanation:

We prove the polynomial with factorization. We must first simplify the expression before we can factorize:

(4\cdot{x^2}-2)\cdot{(4\cdot{x^2}-2)}-16\cdot{x^4}

16\cdot{x^4}-8\cdot{x^2}-8\cdot{x^2}+4-16\cdot{x^4}

4-16\cdot{x^2}

4 is the common number and we can take it out of the expression:

4\cdot{(1-4\cdot{x^2})}

We can factorize further with the x term being zero. For this to be true we must have -2x and 2x to cancel out and therefore the expression is proven:

4\cdot{(1-2\cdot{x})}\cdot{(1+2\cdot{x})}

5 0
3 years ago
Find the area of the shaded region. Please help! <br><br> Brainliest to who gets it right !
damaskus [11]
0.367 centimeters squared

7 0
3 years ago
Show that every triangle formed by the coordinate axes and a tangent line to y = 1/x ( for x &gt; 0)
vfiekz [6]

Answer:

Step-by-step explanation:

given a point (x_0,y_0) the equation of a line with slope m that passes through the  given point is

y-y_0 = m(x-x_0) or equivalently

y = mx+(y_0-mx_0).

Recall that a line of the form y=mx+b, the y intercept is b and the x intercept is \frac{-b}{m}.

So, in our case, the y intercept is (y_0-mx_0) and the x  intercept is \frac{mx_0-y_0}{m}.

In our case, we know that the line is tangent to the graph of 1/x. So consider a point over the graph (x_0,\frac{1}{x_0}). Which means that y_0=\frac{1}{x_0}

The slope of the tangent line is given by the derivative of the function evaluated at x_0. Using the properties of derivatives, we get

y' = \frac{-1}{x^2}. So evaluated at x_0 we get m = \frac{-1}{x_0^2}

Replacing the values in our previous findings we get that the y intercept is

(y_0-mx_0) = (\frac{1}{x_0}-(\frac{-1}{x_0^2}x_0)) = \frac{2}{x_0}

The x intercept is

\frac{mx_0-y_0}{m} = \frac{\frac{-1}{x_0^2}x_0-\frac{1}{x_0}}{\frac{-1}{x_0^2}} = 2x_0

The triangle in consideration has height \frac{2}{x_0} and base 2x_0. So the area is

\frac{1}{2}\frac{2}{x_0}\cdot 2x_0=2

So regardless of the point we take on the graph, the area of the triangle is always 2.

6 0
3 years ago
Does the following scenario represent independent or dependent events?
ra1l [238]
Independent
Hope this helps :)
Can I have brainliest
5 0
3 years ago
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