Answer:
simple
Explanation:
The glow stick's outer plastic tube holds a solution of an oxalate ester and an electron-rich dye along with a glass vial filled with a hydrogen peroxide solution. ... Glow sticks light up when oxalate esters react with hydrogen peroxide to form a high-energy intermediate
Answer:
13-b
Explanation:
because 13-b is close to a and 12
Answer:
The specific heat of the sample unknown metal is approximately 0.45 J/g °C.
General Formulas and Concepts:
<u>Thermodynamics</u>
Specific Heat Formula: 
- <em>m</em> is mass (g)
- <em>c</em> is specific heat capacity (J/g °C)
- Δ<em>T</em> is the change in temperature
Explanation:
<u>Step 1: Define</u>
<em>Identify variables.</em>
<em>m</em> = 112 g
Δ<em>T</em> = 20.0 °C
<em>q</em> = 1004 J
<u>Step 2: Solve for </u><u><em>c</em></u>
- Substitute in variables [Specific Heat Formula]:

- Simplify:

- Isolate <em>c</em>:

- Round [Sig Figs]:

∴ specific heat capacity <em>c</em> is equal to around 0.45 J/g °C.
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Topic: AP Chemistry
Unit: Thermodynamics
Answer:
2. Have the property of metals and non-metals
Explanation:
A metalloid is a substance that posseses the characteristics of both metals and non-metals. In other words, it can be said to be an intermediary between metals and nonmetals.
According to this question, a metalloid