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NNADVOKAT [17]
3 years ago
5

Why are gamma rays not able to reflect off a mirrors surface

Chemistry
2 answers:
ElenaW [278]3 years ago
7 0

Answer:

the Ray's go right through it

Explanation:

the Ray's are so small they punch right through them

givi [52]3 years ago
7 0

Answer:

Explanation:

The reason why is based in something called the plasma frequency of the metal of a mirror. A metal, as you may know, is composed of a series of atom (ion, effectively) cores - nuclei, together with some, but not all, of their bound electrons - which contribute the remaining outermost electrons of their unbound forms to a communally shared "electron sea" - kind of like a giant, distributed omnidirectional covalent bond that extends all throughout the whole metal crystal (here we're just considering a single crystal for simplicity). The electrons are quantumed out all over the full extent of the crystal and effectively form a sort of "gas" throughout and permeating the metal.

When an electromagnetic wave approaches that gas, the free charges within it - the electrons - start oscillating, and as they do so, they set up another wave going outward at the same time as the first is going in. This begins as soon as the first wave begins to impinge.

However, if the wave oscillation is fast enough, the electrons can't keep up due to their mass, and thus they are unable to form the reflected wave. The frequency at which this occurs is called the metal's plasma frequency (and is inversely proportional to the square root of the mass, so that a high mass particle would have a lower plasma frequency). The name comes from the fact that the metal can be thought of in a sense as a kind of "solid plasma" - ions with free electrons, the difference with what most people think of as a "plasma" being here the ions are not free to move about of their own accord.

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Answer:

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Explanation:

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Answer:

The correct options are "b" and "c". A further explanation is given below.

Explanation:

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The other options offered aren't relevant to the situation described. So the equivalents above are the right ones.

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Given the following cations, list them in the expected order from smallest to largest: Y3+, Nb3+, Sb3+
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<u>Answer:</u> Antimony ion is the smallest and yttrium ion is the largest.

<u>Explanation:</u>

Atomic radius of an atom is defined as the total distance from the nucleus to the outermost shell of the atom.

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  • When an atom gains electrons, it results in the formation of negative ion known as anion.

As moving from left to right in a period, more and more electrons get added up in the same shell and the attraction between the last electron and nucleus increases, which results in the shrinkage of size of an atom. Hence, the size of an atom decreases.

The size of the cation is small then their neutral atom because it has less number of electrons while its nuclear charge remains the same. Thus, the nucleus attracts the electron more towards itself and leads to the decrease in size.

We are given three cations:  Y^{3+},Nb^{3+}\text{ and }Sb^{3+}

Yttrium lies in Period 5, group 3 of the periodic table.

Niobium lie in Period 5, group 5 of the periodic table.

Antimony lies in Period 5, group 15 of the periodic table.

So, the order of atomic radii in increasing order follows:

Sb^{3+}

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