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serious [3.7K]
4 years ago
14

What mass of calcium carbonate (in grams) can be dissolved by 4.0 g of hcl? (hint: begin by writing a balanced equation for the

reaction between hydrochloric acid and calcium carbonate.)?
Chemistry
2 answers:
stiks02 [169]4 years ago
8 0
The reaction between calcium carbonate and hydrochloric acid can be expressed through the chemical reaction,

    CaCO3 + 2HCl --> CaCl2 + H2O + CO2

The molecular weight of calcium carbonate is 100 g/mol while that of hydrochloric acid is 36.45. The equation above depicts that 100 g of calcium carbonate can be dissolved in 72.9 g of hydrochloric acid. 

    x = (4 g HCl)(100 g CaCO3 / 72.9 HCl)
      x = 5.49 g

Answer: 5.49 g
Paha777 [63]4 years ago
3 0

Answer:

4 grams of HCl need 5.486 grams of CaCO3

Explanation:

The balanced chemical reaction between hydrocloric acid and calcium carbonate can be expressed as

CaCO3+ 2HCl -> CaCl2 + CO2 + H2O

This means that 1 mole of CaCO3 reacts with 2 mole of HCl to produce 1 mole of CaCl2,CO2 and H2O.

2 mole of HCl needs 2 mole of CaCO3  

In term of mass we can write that

72.9 grams of HCl need 100 grams of CaCO3

1 grams of HCl need (100/72.9) grams of CaCO3

4 grams of HCl need ((100*4)/72.9) grams of CaCO3

4 grams of HCl need 5.486 grams of CaCO3

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3 years ago
18. give the product for the following reactions sequence. a) 3-pentanone b) 2-pentanone c) propanone d) 2-butanone e) methyl pr
serg [7]

The product for the following reaction are :

  • 2 - butanone
  • CH₃CH₂COCl
  • CH₃CH₂CONHCH₃

T carboxylic acid is an organic compound. the functional group of carboxylic acid is carboxy. general formula is given as : R - COO⁻.

The reactions are given as follows :

1) the reduction of carboxylic acid into ketone with the organometallic compound is given as follows :

CH₃CH₂COOH     +  CH₃Li   ------>   CH₃CH₂COCH₃

                                                                  2 butanone

2) the reaction of carboxylic acid with SOCl₂ is given as follows :

CH₃CH₂COOH    +   SOCl₂   ----->   CH₃CH₂COCl

3) the reaction of carboxylic acid with CH₃NH₂ is given as follows

CH₃CH₂COOH  +   CH₃NH₂   ----->   CH₃CH₂CONHCH₃

Thus,  The product for the following reaction are :

  • 2 - butanone
  • CH₃CH₂COCl
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5 0
1 year ago
A 15.0 mL solution of Sr(OH)2 is neutralized with 38.5 mL of 0.350 M
Darya [45]

Answer:

Molarity of Sr(OH)₂  = 0.47 M

Explanation:

Given data:

Volume of Sr(OH)₂ = 15.0 mL

Volume of HCl = 38.5 mL (0.0385 L)

Molarity of HCl = 0.350 M

Concentration/Molarity of Sr(OH)₂  = ?

Solution:

Chemical equation:

Sr(OH)₂ + 2HCl     →      SrCl₂ +2H₂O

Number of moles of HCl:

Molarity = number of moles/ volume in L

0.350 M = number of moles/0.0385 L

Number of moles = 0.350 mol/L× 0.0385 L

Number of moles = 0.0135 mol

Now we will compare the moles of HCl with Sr(OH)₂.

                    HCl       :     Sr(OH)₂

                      2         :         1

                   0.0135   :      1/2×0.0135 = 0.007 mol

Molarity/concentration of Sr(OH)₂:

Molarity = number of moles / volume in L

Molarity = 0.007 mol /0.015 L

Molarity = 0.47 M

7 0
3 years ago
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