The absolute value is defined as

So for example, if <em>x</em> = 3, then |<em>x</em>| = |3| = 3, since 3 is positive. On the other hand, if <em>x</em> = -5, then |<em>x</em>| = |-5| = -(-5) = 5, since -5 is negative. The absolute value is always positive.
For the inequality |7 + 8<em>x</em>| > 5, you consider the two cases where the argument to the absolute value (the expression you find inside the bars) is either positive or negative.
• If 7 + 8<em>x</em> ≥ 0, then |7 + 8<em>x</em>| = 7 + 8<em>x</em>, so that

• Otherwise, if 7 + 8<em>x</em> < 0, then |7 + 8<em>x</em>| = -(7 + 8<em>x</em>), so that

The solution to the inequality is the union of these two intervals.
Answer:
1/3 times 1/3
Step-by-step explanation:
the answer is 1/3 * 1/3 because when you divide with fraction you make the 3 or 3/1 turned around which is 1/3, then you multiply 1/3 * 1/3
Answer:
6
Step-by-step explanation:
it goes by two so I think it'll be six , not so sure tho :)
Answer:
2nd one
Step-by-step explanation:
The volume of a sphere is (4/3) (pi) (radius cubed).
The volume of one sphere divided by the volume of another one is
(4/3) (pi) (radius-A)³ / (4/3) (pi) (radius-B)³
Divide top and bottom by (4/3) (pi) and you have (radius-A)³ / (radius-B)³
and that's exactly the same as
( radius-A / radius-B ) cubed.
I went through all of that to show you that the ratio of the volumes of two spheres
is the cube of the ratio of their radii.
Earth radius = 6,371 km
Pluto radius = 1,161 km
Ratio of their radii = (6,371 km) / (1,161 km)
Ratio of their volumes = ( 6,371 / 1,161 ) cubed = about <u>165.2</u>
Note:
I don't like the language of the question where it asks "How many spheres...".
This seems to be asking how many solid cue balls the size of Pluto could be
packed into a shell the size of the Earth, and that's not a simple solution.
The solution I have here is simply the ratio of volumes ... how many Plutos
can fit into a hollow Earth if the Plutos are melted and poured into the shell.
That's a different question, and a lot easier than dealing with solid cue balls.