Answer:
Piso = 32.17 Torr
Pprop = 5.079 Torr
yprop = 0.1364
yiso = 0.8636
Explanation:
From the question; we can opine that :
- The mole fraction of isopropanol in a mixture of isopropanol and propanol will be 1.
-
The partial pressure of isopropanol will be its mole fraction multiplied by vapor pressure of isopropanol
-
The partial pressure of propanol will be its mole fraction multiplied by vapor pressure of propanol
-
In the vapor, the mole fraction of propanol will be its partial pressure divided by the sum of the two partial pressures
NOW;
When xprop = 0.243; xisopropanol will be 1- 0.243 = 0.757
P°iso = 45.2 Torr at 25 °C so
Piso will be 45.2 × 0.757 = 32.17 Torr
Pprop will be 20.9 × 0.243 = 5.079 Torr
yprop = 5.079/(5.079 +32.17) = 0.1364
yiso = 1-0.1364 = 0.8636
Answer:
Explanation:
Since this problem is incomplete, let us give a simple explanation to solve it.
In any reaction, we always have reactants that are in short supply and those that are in excess.
A reactant in short supply in a reaction is called the limiting reagent. This reactant will usually determine the extent of the reaction. When it is used up, the reaction will stop and will not proceed further.
To solve for the limiting reagent, convert the given mass to number of moles. Always work with number of moles.
Then write the balanced reaction equation.
Compare the moles from the balanced equation to that obtained. The reacting specie that is lesser in proportion is the limiting reagent
To solve the second part;
Compare the number of moles of the limiting reactant to that of the product i.e H₂O;
Use this number of moles to find mass;
Mass of H₂O = number of moles x molar mass
Answer:
Empirical formula is C3H3O
Molecular formula C9H9O3
Explanation:
From the question given, we obtained the following data:
Carbon = 63.15%
Hydrogen = 5.30%
Oxygen = 31.55%
We can obtain the empirical and molecular formula by doing the following as illustrated in the attached file. Please see attachment for explanation.
Methane is CH4
Ethane is. C2H6
Method by ☆cracking alkanes☆
In this case, by cracking methane
Cracking alkanes is the method used to split a long alkane structure into smaller alkanes using high temperature and a catalyst.
e.g. C2H6 -> CH4 + CH2
