Answer:

Explanation:
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In this case, since the formula for the calculation of molarity is:

Whereas we can compute the moles of the solute as shown below, making sure the volume is in liters:

Thus, by plugging in we obtain:

Next, since the molar mass of NaCl is 58.44 g/mol, we obtain the following mass:

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Answer:
The correct answer is Polar structure. See the explanation below, please.
Explanation:
The water molecule is formed by the union of an oxygen atom (O) to two hydrogen atoms (H), forming at an angle of 105 °, having the negative electron density over the O and positive over the H. The water due to its polarity can interact with other equal molecules, by hydrogen bridge (occurs between the atom of H and an electronegative element, in this case the O). It corresponds to a type of dipole-dipole interaction.
Answer:
pH= 12.7
Explanation:
a)Keep an emergency kit and fresh water in your car in the event of _an unexpected event.
b) pOH= -log[OH-]
pOH= -log[5.00×10^-2]
pOH= 1.3
But pH+pOH= 14
pH= 14-pOH= 14-1.3
pH= 12.7
Answer:
60 grams
Explanation:
We have the balanced equation (without state symbols):
6
H
2
O
+
6
C
O
2
→
C
6
H
12
O
6
+
6
O
2
So, we would need six moles of carbon dioxide to fully produce one mole of glucose.
Here, we got
88
g
of carbon dioxide, and we need to convert it into moles.
Carbon dioxide has a molar mass of
44
g/mol
. So here, there exist
88
g
44
g
/mol
=
2
mol
Since there are two moles of
C
O
2
, we can produce
2
6
⋅
1
=
1
3
moles of glucose
(
C
6
H
12
O
6
)
.
We need to find the mass of the glucose produced, so we multiply the number of moles of glucose by its molar mass.
Glucose has a molar mass of
180.156
g/mol
. So here, the mass of glucose produced is
1
3
mol
⋅
180.156
g
mol
≈
60
g
to the nearest whole number.
So, approximately
60
grams of glucose will be produced.
Molality is defined as the number of moles of solute in 1 kg of solvent.
molality of solution to be prepared is 0.50 molal
this means that in 1000 g of water there should be 0.50 mol of NaCl
if 1000 g of water should contain - 0.50 mol
then 750.0 g of water requires - 0.50 mol/kg x 0.750 kg = 0.375 mol
mass of NaCl in 0.375 mol - 58.5 g/mol x 0.375 mol = 21.9 g
therefore a mass of 21.9 g of NaCl is required