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2 years ago

Can a tank of oxygen gas ever be half empty? pls explain

2 answers:

6 0

If you're talking about the Oxygen that we breath, In a form of Gas, no it can't. Because when the number of molecules reaches the half, The Pressure will drop, and the Molecules will cover the empty spaces.

But if you're talking about the Oxygen that is used medicals and food industry, yes it can. Because it's mixed with something and filled at a very High pressure. This Oxygen we don't breath it.

Hope this Helps :)

3241004551 [841]2 years ago

4 0

no, it just cant...

Oxygen is like air so can air ever be half empty with all of us breathing ?

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In which liquid does solid brass float?

ch4aika [34]

Answer:

Explanation:

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3 years ago

Read 2 more answers

d) A short ton of coal holds about 2.24 x 107 J of energy and costs about $56.45 per short ton. How many Joules of energy in the

Feliz [49]

Answer:

396811.337 J

Explanation:

The cost of one short ton of coal = $56.45

The energy related to the short ton of coal = $2.24\times 10^{7}\ J$

Thus, As according to the question,

$56.45 of coal have $2.24\times 10^{7}\ J$ of energy.

$1 of coal have $\frac{2.24\times 10^{7}}{56.45}\ J$ of energy.

<u>The amount of energy = 396811.337 J</u>

4 0

3 years ago

What is a vocab word for Friction?

Leona [35]

Answer: Friction is the resistance to motion of one object moving relative to another. It is not a fundamental force, like gravity or electromagnetism. Instead, scientists believe it is the result of the electromagnetic attraction between charged particles in two touching surfaces.

Explanation:

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2 years ago

What is the molarity of a solution that has 4.4 moles BaCl2 in 1.5 Liters of solution?

garik1379 [7]

Answer:

2.9 M

Explanation:

Step 1: Given data

Moles of barium chloride (solute): 4.4 moles

Volume of solution: 1.5 liters

Step 2: Calculate the molarity of barium chloride in the solution

The molarity is a way to quantitatively express the concentration of a solute in a solution. The molarity is equal to the moles of solute divided by the volume, in liters, of solution.

$M=\frac{4.4mol}{1.5L} =2.9 M$

7 0

2 years ago

If 72.5 grams of calcium metal (Ca) react with 65.0 grams of oxygen gas (O2) in a synthesis reaction, how many grams of the exce

Natali5045456 [20]

2Ca + O2 = 2CaO
First, determine which is the excess reactant
72.5 g Ca (1 mol) =1.8089725036
(40.078 g)

65 g O2 (1 mol) =2.0313769611
(15.999g × 2)
Since the ratio of to O2 is 2:1 in the balanced reaction, divide Ca's molar mass by 2 to get 0.9044862518. this isn't necessary because Ca is already obviously the limiting reactant. therefore, O2 is the excess reactant.

Now do the stoichiometry
72.5 g Ca (1 mol Ca) (1 mol O2)
(40.078 g Ca)(2 mol Ca)(31.998g O2)

=0.0282669621 g of O2 left over

5 0

3 years ago