Explanation:
I don't know sorry ok I have some work so I m sorry
The heat required to raise the temperature to a specific temperature change of a sample is related to the specific heat capacity of the substance. In this case, the heat can be calculated through mCpΔT = 350 g * 0.39 J/g C *25 C. This is equal to 3412. 5 Joules. Closest answer is C.
The precipitation reaction of sodium nitrate and lead (II) chloride would not happen. No reaction will happen between these substances. Hope this answers the question. Have a nice day.
Answer : The amount of carbon dioxide produced is, 197.12 grams.
Explanation : Given,
Moles of ethanol = 2.24 mole
Molar mass of carbon dioxide = 44 g/mole
The balanced chemical reaction will be,
![C_2H_5OH+3O_2\rightarrow 2CO_2+3H_2O](https://tex.z-dn.net/?f=C_2H_5OH%2B3O_2%5Crightarrow%202CO_2%2B3H_2O)
First we have to calculate the moles carbon dioxide.
From the balanced chemical reaction, we conclude that
As, 1 mole of ethanol react to give 2 moles of carbon dioxide
So, 2.24 mole of ethanol react to give
moles of carbon dioxide
Now we have to calculate the mass of carbon dioxide.
![\text{Mass of }CO_2=\text{Moles of }CO_2\times \text{Molar mass of }CO_2](https://tex.z-dn.net/?f=%5Ctext%7BMass%20of%20%7DCO_2%3D%5Ctext%7BMoles%20of%20%7DCO_2%5Ctimes%20%5Ctext%7BMolar%20mass%20of%20%7DCO_2)
![\text{Mass of }CO_2=4.48mole\times 44g/mole=197.12g](https://tex.z-dn.net/?f=%5Ctext%7BMass%20of%20%7DCO_2%3D4.48mole%5Ctimes%2044g%2Fmole%3D197.12g)
Therefore, the amount of carbon dioxide produced is 197.12 grams.