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ElenaW [278]
3 years ago
13

Metals have low ionization energies and readily share their ________ or outer electrons with each other to form an electron ____

___. These electrons are ________ or shared among all the atoms that are bonded together and can therefore move freely throughout the metal structure.
Chemistry
2 answers:
Arturiano [62]3 years ago
7 0

Answer:

Valence, Sea, Delocalized (Pooled) are the correct answer of this question.

Explanation:

  • Valence usually reflects the amount of electrons available to fill an atom's topmost shell.An molecule's valence is the amount of protons which can interact with or substitute (explicitly or implicitly) one of the molecule's atoms.
  • Its electron marine model is a magnetic attachment method in which cations are assumed to be quantum superpositions within a rotating particle' sea.'
  • Delocalization occurs as orbital angular momentum is distributed through more than one atom.

<u> For example</u>:-bonding electrons can be distributed among many bonded        atoms.

Dmitry [639]3 years ago
3 0

Explanation:

Metals are the species which readily lose electrons in order to attain stability. This electron lost by the atom is actually present in its outermost shell which is also known as valence shell.

Ionization energy is defined as the energy required to remove the most loosely bound electron from a neutral gaseous atom.

When we move across a period from left to right then there occurs a decrease in atomic size of the atoms. Therefore, ionization energy increases along a period.  

But when we move down a group then there occurs an increase in atomic size of the atoms due to addition of number of electrons in the atoms. Hence, ionization energy decreases along a group.

Thus, we can conclude that metals have low ionization energies and readily share their valence or outer electrons with each other to form an electron sea. These electrons are delocalized or shared among all the atoms that are bonded together and can therefore move freely throughout the metal structure.

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Complete the transmutation equation below. Assume that there is only one unknown product. Np93239→Pu94239+?
aliya0001 [1]
I have attached the answer. hopefully, i read the problems correctly. let me know if I did not.

both problems are an example of beta decays. when an atoms' atomic number is increased by one. this is symbolized with -1 e

5 0
3 years ago
Using the standard reduction potentials, Pb 2+(aq) + 2e– =&gt; Pb(s), E° = –0.13 V Fe 2+(aq) + 2e– =&gt; Fe(s), E° = –0.44 V Zn
mojhsa [17]

Answer:

Pb(s), Fe(s) and Zn(s) will reduce Mn^{3+} to Mn^{2+}

Fe(s) and Zn(s) will reduce Cr^{3+} to Cr

Explanation:

Standard reduction potential denotes ability to consume electrons from another species.

Hence, higher the standard reduction potential, higher will be the ability to oxidize another species.

Metal with E_{red}^{0} value lower than 1.51 V will donate electron to Mn^{3+} and thus reduces Mn^{3+} to Mn^{2+}.

So, Pb(s), Fe(s) and Zn(s) will reduce Mn^{3+} to Mn^{2+}.

Metal with E_{red}^{0} value lower than -0.40 V will donate electron to Cr^{3+} and thus reduces Cr^{3+} to Cr.

So, Fe(s) and Zn(s) will reduce Cr^{3+} to Cr.

6 0
3 years ago
Chem quiz please help
GalinKa [24]

The theoretical and percentage yield for the reaction are:

  • The theoretical yield is 21 g
  • The percentage yield is 119%

<h3>Balanced equation </h3>

CH₄ + 2O₂ —> CO₂ + 2H₂O

Molar mass of CH₄ = 16 g/mol

Mass of CH₄ from the balanced equation = 1 × 16 = 16 g

Molar mass of O₂ = 32 g/mol

Mass of O₂ from the balanced equation = 2 × 32 = 64 g

Molar mass of CO₂ = 44 g/mol

Mass of CO₂ from the balanced equation = 1 × 44 = 44 g

SUMMARY

From the balanced equation above,

16 g of CH₄ reacted with 64 g of O₂ to produce 44 g of CO₂

<h3>How to determine the limiting reactant</h3>

From the balanced equation above,

16 g of CH₄ reacted with 64 g of O₂

Therefore,

20 g of CH₄ will react with = (20 × 64 ) / 16 = 80 g of O₂

From the above calculation, a higher mass (i.e 80 g) of O₂ than what was given (i.e 30 g) is needed to react completely with 20 g of CH₄.

Therefore, O₂ is the limiting reactant

<h3>How to determine the theoretical yield of CO₂</h3>

From the balanced equation above,

64 g of O₂ reacted to produce 44 g of CO₂

Therefore,

30g of O₂ will react to produce = (30 × 44) / 64 = 21 g of CO₂

<h3>How to determine the percentage yield </h3>
  • Actual yield of CO₂ = 25 g
  • Theoretical yield of CO₂ = 21 g
  • Percentage yield =?

Percentage yield = (Actual / Theoretical) × 100

Percentage yield = (25 / 21) ×100

Percentage yield = 119%

Learn more about stoichiometry:

brainly.com/question/14735801

#SPJ1

4 0
2 years ago
What coefficient must be added to the carbon in the reactants to balance the following equation?
Sophie [7]

Answer:

2

Explanation:

There are  3 carbons on the right side

there are only two on the left side....you need one more ...so add one more... change the '1' coefficient in front of C   to  '2'

7 0
2 years ago
The atomic mass of oxygen is 16 and the atomic mass of hydrogen is 1. How do the current atomic masses of oxygen and hydrogen co
lina2011 [118]
- Dalton reported that seven pounds of Oxygen reacted with one pound of hydrogen to form water, but accurate modern experiment gives eight pounds to one.
- Lavoisier reported that water contains Oxygen 5.6 times more than hydrogen by weight. 
- Dalton assumed that water contains 1 atom of oxygen and 1 atom of hydrogen and concluded that the relative weight of O must be 5.6 times as large as the H atom.
- By determining the relative mass we will be able to determine for example that one element has twice the mass of a second element.
5 0
2 years ago
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