Answer:
x component 3.88 y- component 14.488
Explanation:
We have given a vector A which has a magnitude of 15 m/sec which is at 75° counter-clock wise ( anti-clock wise) from x -axis which is clearly shown in bellow figure
Now x-component will be 15 cos75°=3.8822 ( as it makes an angle of 75° with x-axis )
y- component will be 15 sin 75°=14.488
For verification the resultant of x and y component should be equal to 15
So
(a) 24.6 Nm
The torque produced by the net thrust about the center of the circle is given by:
where
F is the magnitude of the thrust
r is the radius of the wire
Here we have
F = 0.795 N
r = 30.9 m
Therefore, the torque produced is
(b)
The equivalent of Newton's second law for a rotational motion is
where
is the torque
I is the moment of inertia
is the angular acceleration
If we consider the airplane as a point mass with mass m = 0.741 kg, then its moment of inertia is
And so we can solve the previous equation to find the angular acceleration:
(c)
The linear acceleration (tangential acceleration) in a rotational motion is given by
where in this problem we have
is the angular acceleration
r = 30.9 m is the radius
Substituting the values, we find