Answer:
0.67 s
Explanation:
This is a simple harmonic motion (SHM).
The displacement,
, of an SHM is given by

A is the amplitude and
is the angular frequency.
We could use a sine function, in which case we will include a phase angle, to indicate that the oscillation began from a non-equilibrium point. We are using the cosine function for this particular case because the oscillation began from an extreme end, which is one-quarter of a single oscillation, when measured from the equilibrium point. One-quarter of an oscillation corresponds to a phase angle of 90° or
radian.
From trigonometry,
if A and B are complementary.
At
, 


So

At
, 





The period,
, is related to
by

Answer:
The magnitude of the acceleration is 4.2 m/s²
Explanation:
Given;
initial velocity of the powerful sports car, u = 0
final velocity of the powerful sports car, v = 25 m/s
time of motion, t = 6 seconds
Acceleration = Δv / Δt
Δv is change in velocity
Δt is change in time
The magnitude of the acceleration of the powerful sports car during the motion is given by;

Therefore, the magnitude of the acceleration is 4.2 m/s²
The strength of chemical bonds would be the best answer to this question. Hardness is indirectly related to the strength of chemical bonds. Hardness is the resistance from the destruction of an object itself from a material. Hardness does not need to strength of chemical bonds in order to have this resistance.