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Setler [38]
3 years ago
5

How do we observe in experiments?

Chemistry
2 answers:
defon3 years ago
7 0

Answer: by looking and wrighting notes down

Explanation: brainlist me

erica [24]3 years ago
3 0
By paying close attention of what it doing it or who is doing it
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“Least molecular motion, lowest kinetic energy, strongest forces of attention, most dense packaging of molecules”. Which state o
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3 years ago
Which of the following is used in pencils?
Mamont248 [21]

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1st answer:  A. Graphite

2nd answer:  B.  Mercury

Explanation:

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3 years ago
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The number of valence electrons of the element with the electron configuration 1s22s22p63s23p1 is :
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3
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5 0
3 years ago
the volume of a cylindrical tin can with a top and a bottom is to be 16Ï cubic inches. if a minimum amount of tin is to be used
Hunter-Best [27]

Answer:

The required height of the tin can is given by the height at the minimum value of the surface area function of the tin can

The height of the tin can must be 4 inches

Reason:

The given information on the tin can are;

Volume of the tin can = 16·π in.³

The amount of tin to be used = Minimum amount

The height of the can in inches required

Solution;

Let h, represent the height of the can, we have;

The surface area of the can, S.A. = 2·π·r² + 2·π·r·h

The volume of the can, V = π·r²·h

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r = The radius of the tin can

h = The height of the tin can

Which gives;

16·π = π·r²·h

16 = r²·h

Which gives;

When the minimum amount of tin is used, we have;

Therefore;

4·π·(r³ - 8) = r² × 0

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r = 2

The radius of the tin can, r = 2 inches

The

The height of the tin can, h = 4 inches

Learn more here:

brainly.com/question/14316282

Explanation:

8 0
3 years ago
Which element decreases its oxidation number in this reaction? bicl2 + na2so4 → 2nacl + biso4?
kifflom [539]
The balanced reaction is as follows;
BiCl₂ + Na₂SO₄ --> 2NaCl + BiSO₄
this is a double displacement reaction 
the oxidation number of Bi is +2 in both BiCl₂ and BiSO₄
oxidation number of Cl is -1 in both BiCl₂ and NaCl 
oxidation number of Na is +1 in both Na₂SO₄ and NaCl
oxidation numbers of elements in SO₄²⁻ remains the same in both compounds.Therefore the oxidation state in any of the elements in the reaction doesn't change. Neither of the elements show an increase or decrease in the oxidation numbers .
Answer for this question is no element decreases its oxidation number.

5 0
3 years ago
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