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3 years ago

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What is defined as the basic unit in the metric system that describes a quality?

1 answer:

In-s [12.5K]3 years ago

3 0

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What is defined as the basic unit in the metric system that describes a quality?

Answer:

$\underline{\underline{{My~ Answer~ would ~ be ~ A.\;}}}$

Explanation:

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Why must sample spots be above the solvent in paper chromatography

marishachu [46]

Because if they are submerged in the solvent, they would dissolve! This would prevent them from seperating and not allow you to actually record anything

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3 years ago

It is important to understand that while the absorbance value is related to the amount of light absorbed by a sample, it is not

Trava [24]

When 100 photons of light pass through a sample and 64 photons are detected after the passage of light, the number of photons transmitted through the sample is 64.

This is based on the methods of calculating the absorbance of light, which is depicted as the higher the amount of light transmission, the lower the amount of light absorbed.

Thus, when 64 photons of light in 100 photons are detected, 64 photons are transmitted, and therefore, the number of photons absorbed is 36.

Hence, hypothetically, if 100 photons of light are transmitted, 0 photons of light will be absorbed.

Therefore, in this case, it is concluded that the correct answer is 64 photos.

Learn more here: brainly.com/question/20678715

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2 years ago

g Ammonia has been studied as an alternative "clean" fuel for internal combustion engines, since its reaction with oxygen produc

Gala2k [10]

$\text{Ammonia has been studied as an alternative "clean" fuel for internal combustion}$

$\text{engines, since its reaction with oxygen produces only nitrogen and water vapor,}$

$\text{and in the liquid form it is easily transported. An industrial chemist studying this}$

$\text{reaction fills a} \ \mathbf{100 \ L }\ \text{tank with} \ \mathbf{8.6 \ mol} \ \text{of ammonia gas and} \ \mathbf{28 \ mol} \ \ \text{of oxygen gas, }$

$\text{to be} \ \mathbf{2.6\ mol} \ .\ \text{Calculate the concentration equilibrium constant for the combustion of}$

$\text{ammonia at the final temperature of the mixture. Round your answer to 2 significant digits.}$

Answer:

Explanation:

From the correct question above:

The reaction can be represented as:

$\mathbf{4 NH_3_{(g)}+ 3O_{2(g)} \iff 2N_{2(g)}+ 6H_2O_{(g)} }$

From the above reaction; the ICE table can be represented as:

$\mathbf{4 NH_3_{(g)}+ 3O_{2(g)} \iff 2N_{2(g)}+ 6H_2O_{(g)} }$

I (mol/L) 0.086 0.28 0 0

C -4x -3x +2x +6x

E 0.086 - 4x 0.28 - 3x +2x +6x

At equilibrium;

The water vapor = $\dfrac{2.6 \ mol}{100 \ L} = 6x$

$x = \dfrac{2.6}{100} \times \dfrac{1}{6}$

$x = 0.00433$

$\text{equilibrium constant} ({k_c}) = \dfrac{ [N_2]^2 [H_2O]^6 }{ [[NH_3]^4] [O_2]^3 }$

$\implies \dfrac{(2x)^2 (6x)^6}{(0.086-4x)^4\times (0.28-3x)^3} \\ \\$

Replacing the value of x, we have:

$K_c = \dfrac{4 \times 46,656 \times x^8}{(0.086-4x)^4\times (0.28 -3x)^3} \\ \\ K_c = \dfrac{4 \times 46656 \times (0.00433)^8}{(0.06868)^4(0.26701)^3} \\ \\ K_c = \mathbf{5.4446 \times 10^{-8}}$

$K_c = \mathbf{5.5 \times 10^{-8} \ to \ 2 \ significant \ figures}$

5 0

3 years ago

How much energy is required to melt 10. 0 g of ice at 0. 0°C, warm it to 100. 0°c and completely vaporize the sample?

natta225 [31]

The 7160 cal energy is required to melt 10. 0 g of ice at 0. 0°C, warm it to 100. 0°C and completely vaporize the sample.

Calculation,

Given data,

Mass of the ice = 10 g

Temperature of ice = 0. 0°C

The ice at 0. 0°C is to be converted into water at 0. 0°C

Heat required at this stage = mas of the ice ×latent heat of fusion of ice

Heat required at this stage = 10 g×80 = 800 cal

The temperature of the water is to be increased from 0. 0°C to 100. 0°C

Heat required for this = mass of the ice×rise in temperature×specific heat of water

Heat required for this = 10 g×100× 1 = 1000 cal

This water at 100. 0°C is to be converted into vapor.

Heat required for this = Mass of water× latent heat

Heat required for this = 10g ×536 =5360 cal

Total energy or heat required = sum of all heat = 800 +1000+ 5360 = 7160 cal

to learn more about energy

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1 year ago

Solutions are said to be what kind of mixture? A) Pure substance B) Heterogeneous C) Homogenous D) Element

laiz [17]

Solutions are said to be C. homogeneous mixtures, composed of two or more substances. It is usually liquid, however it may be solid or gas.

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3 years ago