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Dmitry_Shevchenko [17]
3 years ago
9

A mixture of propane and butane is fed into a furnace where it is mixed with air. The furnace exhaust leaves the furnace at 337�

C, 786.0 mmHg and contains only N2, O2, CO2, and H2O. The partial pressure of O2 in the exhaust is 10.38 mmHg and the partial pressure of CO2 in the exhaust is 88.03 mmHg.
1.What is the mole fraction of propane in the fuel stream?
2.What is the mole fraction of water in the exhaust stream?
3.What is the dew point temperature of the exhaust gas?

Chemistry
2 answers:
vagabundo [1.1K]3 years ago
7 0

Answer:

1. 3.29mol

2. 0.125molH2o/mol

3. 52.5'C

Explanation: The step by step explanation are attached to the answer.

babymother [125]3 years ago
3 0

Answer:

Mole fraction of propane = 0.74 mol C₃H₈/mol

Mole fraction of water = 0.29 mol H₂0 /mol

Dew point temperature = 52.5°C

Explanation:

See the attached file for the calculation.

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Answer:

wax, candlewick, and oxygen

Explanation:

The burning of the candle is both a physical as well as a chemical change. The reactants are the substances or the raw materials that are required for a reaction to the process. In the process of burning a candle, the reactants are the fuel which includes wax and wick, and oxygen which is found in the air. The products found at the end of the reaction are carbon dioxide and water vapor.

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Problem 12.002 the molar analysis of a gas mixture at 30°c, 2 bar is 40% n2, 50% co2, 10% ch4. determine
andreev551 [17]
The problem is incomplete. However, there can only be two probable questions for this problem. First, you can be asked the individual partial pressures of each gas. Second, you can be asked the volume occupied by each gas. I can answer both cases for you.

1.

Let's assume ideal gas.
Pressure for N₂: 2 bar*0.4 = 0.8 bar
Pressure for CO₂: 2 bar*0.5 = 1 bar
Pressure for CH₄: 2 bar*0.1 = 0.2 bar

2. For the volume, let's find the total volume first.

V = nRT/P = (1 mol)(8.314 J/mol-K)(30 +273 K)/(2 bar*10⁵ Pa/1 bar)
V = 0.0126 m³
Hence,
Volume for N₂: 0.0126 bar*0.4 = 0.00504 m³
Volume for CO₂: 0.0126*0.5 = 0.0063 m³
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Study the picture below. <br><br><br><br><br><br>Done!! Thanks ​
myrzilka [38]

The rabbit and the girl are living things.

The shoe and the skirt are non-living things.

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3 years ago
In which region is the substance in both the solid phase and the liquid phase ?
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In which region is the substance in both the solid phase and the liquid phase ?
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What is the percent composition by mass of each element in Co(HSO4)2?
MrRissso [65]

Answer:

54.1 % Ca, 43.2 % O, 2.7% H

Explanation:

Molecular formula for calcium hydroxide is Ca(OH)₂

As we don't have a mass of Ca(OH)₂ to find out the percentage composition, we consider that the question refers to 1 mol of compound.

1 mol of hydroxide weighs 74.08 g

1 mol of hydroxide has 1 mol of Ca, therefore 40.08 g are Ca

2 moles of O therefore 32g are O

2 moles of H therefore 2 g are H

Percentage composition is known as (Mass of element/Total mass) . 100

(40.08 / 74.08) . 100 = 54.1 %

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(2 / 74.08) . 100 = 2.7%

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