A mixture of propane and butane is fed into a furnace where it is mixed with air. The furnace exhaust leaves the furnace at 337�
C, 786.0 mmHg and contains only N2, O2, CO2, and H2O. The partial pressure of O2 in the exhaust is 10.38 mmHg and the partial pressure of CO2 in the exhaust is 88.03 mmHg.
1.What is the mole fraction of propane in the fuel stream?
2.What is the mole fraction of water in the exhaust stream?
3.What is the dew point temperature of the exhaust gas?
1.What is the mole fraction of propane in the fuel stream?
2.What is the mole fraction of water in the exhaust stream?
3.What is the dew point temperature of the exhaust gas?
2 answers:
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Answer:
Explanation:
In this case, we can start with the reaction:
If we check the reaction, we will have 2 X and Y atoms on both sides. So, <u>the reaction is balanced</u>. Now, the problem give to us two amounts of reagents. Therefore, we have to find the <u>limiting reagent</u>. The first step then is to find the moles of each compound using the <u>molar mass</u>:
Now, we can <u>divide by the coefficient</u> of each compound (given by the balanced reaction):
The smallest value is for "X", therefore this is our <u>limiting reagent</u>. Now, if we use the <u>molar ratio</u> between "X" and "XY" we can calculate the moles of XY, so:
Finally, with the molar mass of "XY" we can calculate the grams. Now, we know that 1 mol X = 85 g X and 1 mol = 48 g
(therefore 1 mol Y = 24 g Y). With this in mind the <u>molar mass of XY</u> would be 85+24 = 109 g/mol. With this in mind:
I hope it helps!