Answer:
(a). The strength of the magnetic field is 0.1933 T.
(b). The magnetic flux through the loop is zero.
Explanation:
Given that,
Radius = 11.9 cm
Magnetic flux
(a). We need to calculate the strength of the magnetic field
Using formula of magnetic flux
Put the value into the formula
(b). If the magnetic field is directed parallel to the plane of the loop,
We need to calculate the magnetic flux through the loop
Using formula of flux
Here,
Hence, (a). The strength of the magnetic field is 0.1933 T.
(b). The magnetic flux through the loop is zero.
I believe it is the neutron and the proton cloud because the electron cloud orbits on the outside
Answer:
a) y = 162.6 m
, b) R = 928.64 m
Explanation:
We will solve this exercise using projectile launch kinematics, as the initial velocities and angle are equal on the planet and the Earth, let's look for the gravedd coinage of the planet
Earth
R = v₀² sin 2θ / g
R g = v₀² sin 2θ
In the planet
4.8 R = v₀² sin 2θ /
4.8 R = v₀² sin 2θ
4.8 R = R g
= g / 4.8
= 9.8 / 4.8
= 2.04 m / s²
Now we can answer the questions
a) The maximum height
Vy² = ² - 2 g y
For ymax the vertical speed is zero ( = 0)
sin θ = /
= sinθ
= 44.9 sin 35
= 25.75 m/s
y = ²/2
y = 25.75² / (2 2.04)
y = 162.6 m
b) the scope
R = v₀² sin 2θ /
R = 44.9² sin 2 35 / 2.04
R = 928.64 m
Answer:
A Parallel circuit has certain characteristics and basic rules: A parallel circuit has two or more paths for current to flow through. Voltage is the same across each component of the parallel circuit. The sum of the currents through each path is equal to the total current that flows from the source.
Explanation:
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Pluto is not part of the solar system