Assume a maximum stopping acceleration of g/2 where g is acceleration due to gravity.
Answer:
2.99 m/s
Explanation:
Stopping distance, s = 3 ft = 0.914 m
final velocity, v = 0
a = g/2 = 4.9 m/s²
Use third equation of motion:

substitute the values to find the speed of train:

Answer: A 120 metros por segundo
Explanation: multiplicas la velocidad por el tiempo
<span>The
_______ is the the distance between two crests or two troughs on a
transverse wave. It is also the distance between compressions or the
distance between rarefactions on a longitudinal wave.</span>
Answer:
From shortest wavelength to longest wavelength:
Gamma Rays
X-Rays
Ultraviolet
Visible Light
Infrared waves
Microwaves
Radio Waves
Explanation: