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3 years ago

Predict how monarch butterfly populations may compare over time in two locations with very different temperatures.

Physics

1 answer:

antoniya [11.8K]3 years ago

3 0

Answer:

they will increase why because they go from warm cold warm meaning they have to adapt back to the previous location

Explanation:

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Three identical train cars, coupled together are rolling east at 2.0 m/s. A fourth car traveling east at 4.0 m/s catches up with

Ann [662]

Answer:

The value is $v = 2 \ m/s$

Explanation:

From the question we are told that

The velocity of the each of the three cars is $u_1 = u_2 = u_3 = 2 \ m/s$

The velocity of the fourth car is $u_4 = 4 \ m/s$

The initial velocity of the fifth car $u_5 = 0 \ m/s$

Generally from the law of momentum conservation we have that

$m_1 u_1 + m_2 u_2 + m_3 u_3 +m_4u_4 + m_5u_5 = [m_1 + m_2 + m_3 +m_4+ m_5]v$

Given that the cars are identical then their mass will be the same

i.e

$m_1 =m_2 = m_3 = m_4 = m_5 = m$

=> $[u_1 + u_2 + u_3 +u_4 + u_5]m = 5mv$

=> $2+ 2 + 2 +4 + 0 = 5v$

= > $v = 2 \ m/s$

8 0

3 years ago

Most metals are in the liquid state at room temperature.

aivan3 [116]

Answer:

Most metals are in the liquid state at room temperature.<u>False</u><u>.</u>

Explanation:

it needs excess heat except mercury and lithium.

4 0

3 years ago

Read 2 more answers

you decide to measure the mass of an aircraft carrier in the CGS system.What unit does your measurement end up in?

Pavel [41]

Pounds I believe? if not then I recommend google :)

6 0

4 years ago

30 points!

vlada-n [284]

Answer:

Since strong nuclear forces involve only nuclear particles (not electrons, bonds, etc) items 3 and 4 are eliminated.

Again item 2 refers to bonds between atoms and is eliminated.

This leaves only item 1.

Nuclear forces are very short range forces between components of the nucleus.

Weak nuclear forces are trillions of times smaller than strong forces.

Gravitational forces are much much smaller than the weak nuclear force.

6 0

3 years ago

Starting from home, you bicycle 25 km north in 2.4 h and then turn around and pedal straight home in 1.4 h . What are your (a) d

AnnZ [28]

Answer:

Part a)

$d = 25 km$

Part b)

$v_{avg} = 10.42 km/h$

Part c)

$v_{avg} = 17.86 km/h$

Part d)

Displacement for entire trip = 0

Part e)

Average velocity for entire trip will be zero

Explanation:

Part a)

Displacement after t = 2.4 hours is the straight line distance between initial and final positions

so we have

$d = 25 km$

Part b)

Average velocity is defined as

$v_{avg} = \frac{displacement}{time}$

$v_{avg} = \frac{25 km}{2.4 h}$

$v_{avg} = 10.42 km/h$

Part c)

During his return journey the displacement will be same

$displacement = 25 km$

$time = 1.4 h$

so average velocity is defined as

$v_{avg} = \frac{25 km}{1.4 h}$

$v_{avg} = 17.86 km/h$

Part d)

Displacement for entire trip = 0

as initial and final position will be same

Part e)

Average velocity for entire trip will be zero

6 0

3 years ago