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kherson [118]
3 years ago
15

Potassium-40 has a half-life of 1.277 x 109 years. After 1.022 x 1010 years, how much potassium-40 will remain from a 500.3-g sa

mple?
A. approximately 1.95 g
B. approximately 3.91 g
C. approximately 62.54 g
D. approximately 71.47 g
Chemistry
2 answers:
Kitty [74]3 years ago
5 0
Approximately 1.95 g
jeyben [28]3 years ago
4 0

Answer:

The correct answer is option A.

Explanation:

Half life of the potassium-40 sample =t_{\frac{1}{2}}= 1.277\times 10^9 years

N = amount left after time t  = ?

Time = t =  1.277\times 10^9 years

N_0 = initial amount  = 500.3 g

\lambda = rate constant

\lambda =\frac{0.693}{t_{\frac{1}{2}}}=\frac{0.693}{ 1.277\times 10^9 years}= 0.5426\times 10^{-9} year^{-1}

\log N=\log N_o\times -\frac{\lambda t}{2.303}

N = 1.95 g

Hence, the correct answer is option A.

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