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natulia [17]
3 years ago
11

A 1,300 kg wrecking ball hits the building at 1.07 m/s2.

Physics
2 answers:
dezoksy [38]3 years ago
7 0
So we know F=ma
m means mass and a means acceleration
so Force= ma
so F=1300X1.07=1391N
hope you like it
if it helps you please mark the answer as brainliest answer
tatuchka [14]3 years ago
6 0

F (force) = mass × acceleration.

<em>The unit N (Newton) is known as kilogram-meter/seconds2. </em>

<u>Thus, F = 1300 kg × 1.07 m/s2 = 1391 N. </u>

<u>The answer is 1391 N.</u>

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When you jump, you exert a pushing force against the ground. Gravity pulls you back down. Why can a person jump higher on the mo
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What is the magnitude of δv12 if the bulb is removed from the socket (i.e. the circuit is not closed)?
andreev551 [17]

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4 0
3 years ago
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7. Calculations.
kotykmax [81]

Answer:

5 ms-2

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F = ma

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4 0
3 years ago
What is the magnitude of the gravitational force acting on the earth due to the sun?
expeople1 [14]

Answer: 3.524(10)^{22}N

Explanation:

According to Newton's law of Gravitation, the force F exerted between two bodies of masses m1 and m2  and separated by a distance r  is equal to the product of their masses and inversely proportional to the square of the distance:

F=G\frac{(m1)(m2)}{r^2}   (1)

Where:

G is the Gravitational Constant and its value is 6.674(10)^{-11}\frac{m^{3}}{kgs^{2}}  

m1=1.99(10)^{30}kg is the mass of the Sun

m2=5.972(10)^{24}kg is the mass of the Earth

r=1.50(10)^{11}m  is the distance between the Sun and the Earth

Substituting the values in (1):

F=6.674(10)^{-11}\frac{m^{3}}{kgs^{2}}\frac{(1.99(10)^{30}kg)(5.972(10)^{24}kg)}{(1.50(10)^{11}m)^2}   (2)

Finally:

F=3.524(10)^{22}N   This is the gravitational force acting on the earth due to the sun

3 0
3 years ago
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