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MariettaO [177]
3 years ago
10

The momentum of an object is determined to be 7.2 ×× 10-3 kg⋅m/skg⋅m/s. Express this quantity as provided or use any equivalent

unit. (Note: 1 kgkg = 1000 gg).
Physics
1 answer:
7nadin3 [17]3 years ago
8 0

Answer:

Momentum, p = 720 g-cm/s

Explanation:

The momentum of an object is determined to be,

p=7.2\times 10^{-3}\ kg-m/s

We need to express this quantity in any equivalent units. We know that the conversions are as follows :

1 kg = 1000 g

and 1 m = 100 cm

p=7.2\times 10^{-3}\ kg-m/s=7.2\times 10^{-3}\times (1000\ g)\times (100\ cm)/s

p = 720 g-cm/s

So, the momentum of an object in any equivalent unit is 720 g-cm/s. Hence, this is the required solution.

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5 0
2 years ago
In mammals, the weight of the heart is approximately 0.5% of the total body weight. Write a linear model that gives the heart we
hammer [34]

Answer:

1201 lbs

Explanation:

Given that in mammals, the weight of the heart is approximately 0.5% of the total body weight.

Let the weight of the heart of a mammal be H

And the weight of the total body be B

The linear model that can gives the heart weight in terms of the total body weight will be:

H = 0.005B

B.) To find the weight of the heart of a whale whose weight is 2.402 × 105 lbs, substitute the whole weight in the formula.

H = 0.005 × 2.402 × 10^5

H = 1201 lbs

Therefore, the weight of the heart of the whale is 1201 lbs

8 0
2 years ago
A person lifts a 25 kg box of old sports equipment at an angle of 75 degrees to the vertical to a shelf 2.6 meters above. How mu
kogti [31]

Answer:

164.87 J

Explanation:

From the question,

Work done (W) = mghcosθ........................ Equation 1

Where m = mass of the box, h = height, g = acceleration due to gravity, θ = angle to the vertical

Given: m = 25 kg, h = 2.6 meters, θ = 75°.

Constant: g = 9.8 m/s²

Substitute these value into equation 1

W = 25×9.8×2.6×cos75°

W = 164.87 J.

6 0
2 years ago
An airplane propeller is rotating at 1900 rpm (rev/min).
alexandr1967 [171]

Answer:

See explanation

Explanation:

We have to convert to angular velocity in rads-1 as follows;

Angular velocity in rad/s = 2π/60 × 1900 rpm = 199 rad/s

Given that

angular velocity =angle turned /time taken

Time taken = angle turned/angular velocity

Converting 35° to radians we have;

35 × π/180 = 0.61 radians

Time taken = 0.61 radians/199 rad/s

Time taken = 0.0031 seconds

3 0
2 years ago
One event occurs at the origin at t equal to zero, and a second events occurs at the point x=5m along the x-axis at time with ct
Anastasy [175]

Answer:

  • The separation will be spacelike.
  • The first event can't cause the second event, as there exist an frame of reference in which both happens at the same time, in different positions, so, if there were causally connected, it will imply an instant connection, this is faster than light.

Explanation:

We can define the separation between two events (using the + - - - signature)  as :

(\Delta s )^2  = (ct_2 - c t_1 )^2 - (x_2 - x_1)^2

where the separation will be lightlike if is equal to zero, timelike if is positive and spacelike if is negative.

For our problem

c t_1 = 0

x_1 = 0

ct_2 = 4 \ m

x_2 = 5 \ m

(\Delta s )^2  = (4 \ m - 0 )^2 - ( 5 \ m - 0)^2

(\Delta s )^2  = (4 \ m )^2 - ( 5 \ m 0)^2

(\Delta s )^2  = 16 \ m^ 2 - 25 \ m^2

(\Delta s )^2  = - 9\ m^2

So the separation will be spacelike, and the first event can't cause the second event, as there exist an frame of reference in which both happens at the same time, in different positions, so, if there were causally connected, it will imply an instant connection, this is faster than light.

8 0
3 years ago
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