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MariettaO [177]
3 years ago
10

The momentum of an object is determined to be 7.2 ×× 10-3 kg⋅m/skg⋅m/s. Express this quantity as provided or use any equivalent

unit. (Note: 1 kgkg = 1000 gg).
Physics
1 answer:
7nadin3 [17]3 years ago
8 0

Answer:

Momentum, p = 720 g-cm/s

Explanation:

The momentum of an object is determined to be,

p=7.2\times 10^{-3}\ kg-m/s

We need to express this quantity in any equivalent units. We know that the conversions are as follows :

1 kg = 1000 g

and 1 m = 100 cm

p=7.2\times 10^{-3}\ kg-m/s=7.2\times 10^{-3}\times (1000\ g)\times (100\ cm)/s

p = 720 g-cm/s

So, the momentum of an object in any equivalent unit is 720 g-cm/s. Hence, this is the required solution.

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A 1.50-m string of weight 0.0125 N is tied to the ceil- ing at its upper end, and the lower end supports a weight W. Ignore the
Elena L [17]

The wave equation is missing and it is y(x,t) = (8.50 mm)cos(172 rad/m x − 4830 rad/s t)

Answer:

A) 0.0534 seconds

B) 0.67N

C) 41

D) (8.50 mm)cos(172 rad/m x + 4830 rad/s t)

Explanation:

we are given weight of string = 0.0125N

Thus, since weight = mg

Then, mass of string = 0.0125/9.8

Mass of string = 1.275 x 10⁻³ kg

Length of string; L= 1.5 m .

mass per unit length; μ = (1.275 x 10⁻³)/1.5

μ = 0.85 x 10⁻³ kg/m

We are given the wave equation: y(x,t) = (8.50 mm)cos(172 rad/m x − 4830 rad/s t)

Now if we compare it to the general equation of motion of standing wave on a string which is:

y(x,t) = Acos(Kx − ω t)

We can deduce that

angular velocity;ω = 4830 rad/s

Wave number;k = 172 rad/m

A) Velocity is given by the formula;

V = ω/k

Thus, V = 4830/172 m/s

V = 28.08 m /s

Thus time taken to go up the string = 1.5/28.08 = 0.0534 seconds

B) We know that in strings,

V² = F/μ

Where μ is mass per unit length and V is velocity.

Thus, F = V²*μ =28.08² x 0.85 x 10⁻³

F = 0.67N

C) Formula for wave length is given as; wave length;λ = 2π /k

λ = 2 x π/ 172

λ = 0.0365 m

Thus, number of wave lengths over whole length of string

= 1.5/0.0365 = 41

D) The equation for waves traveling down the string

= (8.50 mm)cos(172 rad/m x + 4830 rad/s t)

8 0
3 years ago
the dog has a momentum of 60 kilogram meters per second west. the dog has a velocity of 3 meters per second west. what is the ma
lianna [129]
P=mv=>m=p/v=60/3=20kg
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4 years ago
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Assume patmos=1.00atm. what is the gas pressure pgas? express your answer in pascals to three significant figures.
hodyreva [135]
<span>Answer: Well, let's start by finding the pressure due to the "extra" height of the mercury. p = 1.36e4 kg/m³ · (0.105m - 0.05m) · 9.8m/s² = 7330 N/m² = 7330 Pa The pressure at B is clearly p_b = p_atmos = p_gas + 7330 Pa The pressure at A is p_a = p_gas = p_atmos - 7330 Pa c) 1 atm = 101 325 Pa Then p_gas = 101325 Pa - 7330 Pa = 93 995 Pa</span>
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Describe three events that you cannot explain.<br> About energy and matter
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Answer:

A teacher giving homework on fridays

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5 0
3 years ago
The y-position of a damped oscillator as a function of time is shown in the figure.
MrRissso [65]

The length of time that an oscillator is allowed to oscillate, as well as its damping coefficient.

  • t= 1.33s
  • b = 0.0426 s^-1

<h3>What is the period of the oscillator, and what factors influence the amount of damping that it has?</h3>

In most situations, the equation may be expressed numerically as

When we look at the data and see that there are cycles between the timestamps t= 0s and t= 4s, we may conclude that it finishes three cycles once every four seconds. As a result, the length of time that is going to be necessary to finish one cycle of damping will be

t =4/3sec

t= 1.33s

In most situations, the equation for amplitude may be expressed analytically as

A=A_0e^{-bt}

Therefore

3=5e^{-12b}

0.6=e^{-12b}

Therefore

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b = 0.0426 s^{-1}

In conclusion, damping refers to an influence that either operates from inside an oscillatory system or acts on it and has the consequence of reducing or halting the system from oscillating. This impact might occur from either side of the system. In physical systems, damping is produced by processes that cause the energy that is stored in an oscillation to be lost. These processes are called dissipative. The collective name for these processes is "damping agents." The damping coefficient may thus be written as

b = 0.0426 s^-1

Learn more about the damping coefficient by reading up on it.

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4 0
1 year ago
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