2 years ago

Anyone willing to help out really quick?^^

Mathematics

1 answer:

klemol [59]2 years ago

5 0

Answer:

15.86 inches

Step-by-step explanation:

Area of rectangle = length times width

l = ∛81 inches

w = 3 2/3 inches

= l x w

= ∛81 x 3 2/3

= 15.86 inches

You might be interested in

Which of the following expressions is equivalent to the expression a^2/3

vladimir1956 [14]

∛a² → C

From the ' law of exponents '

$a^{\frac{m}{n} }$ = $\sqrt[n]{a^{m} }$

3 0

2 years ago

Two buses leave seattle at the same time and travel in opposite directions. one bus averages 55 mi/h and the other bus averages

nalin [4]

In 4 hours they will be 400 miles apart 4 times 55 is 220 and 4 time 45 is 180 since there going in opposer directions add the miles together and it equals 400 so it takes 4 hours

7 0

3 years ago

What is the slope? Answers 1/5 3/5 6/5 You can only pick one

Amiraneli [1.4K]

1/5 because I said so :)

8 0

2 years ago

Select the problems which show the correct answers. (1.12 x 105) (6.06 x 105) Answer: 6.79 x 1010 (2 x 101)(3.0 x 101) Answer: 6

Arisa [49]

Since multiplication is commutative, we can rearrange the problem:
$(1.12*10^5)(6.06*10^5) = (1.12*6.06)(10^5*10^5)$
Using the properties of exponents, we have:
$(1.12*6.06)(10^10)
\\=6.7872*10^10$

Again, multiplication is commutative, so we rearrange the problem; then we use the product property of exponents:
$(2*10^1)(3*10^1)
\\=(2*3)(10^1*10^1)
\\=6*10^2$

$(2.775*10^-^4)(4.775*10^4)
\\=(2.775*4.775)(10^-^4*10^4)
\\=(2.775*4.775)(10^0)
\\=(2.775*4.775)(1)
\\=2.775*4.775=13.250625=1.3250625*10^1$

$5(8.14*10^2)=(5*8.14)(10^2)=40.7*10^2=4.07*10^3$

6 0

3 years ago

Read 2 more answers

The chu family can hike 3 miles per hour how long will it take them to hike 15 miles

s344n2d4d5 [400]

Answer:

5 hours

Step-by-step explanation:

if they hike 3 miles per 1 hour, and you divide 15 (miles) by 3 (miles) you get 5 hours because each hour they walk 3 miles

(so sorry if this is confusing!! its very hard to explain for me lol)

3 0

2 years ago

Anyone willing to help out really quick?^^​

Anyone willing to help out really quick?^^