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Oksana_A [137]
3 years ago
5

What is one use of the mineral gypsum fertilizer medicine wallboard electrical insulator

Physics
1 answer:
Semmy [17]3 years ago
7 0

Answer:

The main use for gypsum is in the production of Plaster of Paris and drywall products. Gypsum is also used as a soil conditioner.

Explanation:

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Which segment shows the substance changing from a gas to a liquid
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The answer would be w-x 
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(3.8 * 10^-2 cm) * (4.4 * 10^-2 cm) * (7.5 * 10^2 cm)
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Answer:

1.254 cm

Explanation:

(3.8 * 10^-2 cm) = 0.038 cm

(4.4 * 10^-2 cm) = 0.044 cm

(7.5 * 10^2 cm) = 750 cm

0.038 * 0.044 * 750 = 1.254 cm

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You are on an airplane traveling with a constant velocity at an altitude of 20,000m. What is the acceleration of gravity at that
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The correct answer would be A.The acceleration of gravity is <span>9.81 m/s^2. This is calculated by using the equation:

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3 years ago
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A star is estimated to be 4.8 x 10^15 kilometers away from the earth. When we see this star in the night sky, how old is this im
Veseljchak [2.6K]

Answer:

B. 500 years

Explanation:

The light coming from the star and reaching us on the Earth travels with uniform motion (with constant velocity), so we can use the equation of uniform motion which relates distance covered, speed and time taken:

v=\frac{d}{t}

where

v is the speed

d is the distance covered

t is the time taken

In this problem:

v=3.00\cdot 10^8 m/s is the speed at which light travels

d=4.8\cdot 10^{15} km = 4.8\cdot 10^{18}m is the distance that light has to cover from the star to the Earth

Therefore, by rearranging the equation, we can find the time:

t=\frac{d}{v}=\frac{4.8\cdot 10^{18}}{3.00\cdot 10^8}=1.6\cdot 10^{10}s

And by converting into years, this time is

t=\frac{1.6\cdot 10^{10}}{(365)(24)(60)(60)}=507 y

So, approximately 500 years: this means that the image we see of the star is 500 years old.

4 0
3 years ago
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Consider the following equilibrium at 979 K for the dissociation of molecular iodine into atoms of iodine. I2(g) equilibrium rea
GenaCL600 [577]

Answer:  I_2=  0.0050 M

I = 0.0155 M

Explanation:

Initial moles of  I_2 = 0.072 mole

Volume of container = 3.9 L

Initial concentration of I_2=\frac{moles}{volume}=\frac{0.072moles}{3.9L}=0.018M  

The given balanced equilibrium reaction is,

                 I_2(g)\rightleftharpoons 2I(g)

Initial conc.         0.018 M            0

At eqm. conc.    (0.018-x) M      (2x) M  

The expression for equilibrium constant for this reaction will be,

K_c=\frac{[I]^2}{[I_2]}

K_c=\frac{(2x)^2}{0.2-x}

we are given :  K_c=1.60\times 10^{-3}

Now put all the given values in this expression, we get :

1.60\times 10^{-3}=\frac{(2x)^2}{(0.018-x)}

x=0.0025

So, the concentrations for the components at equilibrium are:

[I]=2\times x=2\times 0.0025=0.0050

[I_2]=0.018-x=0.018-0.0025=0.0155

Hence, concentrations of I_2 and I are 0.0050 M ad 0.0155 M respectively.

4 0
3 years ago
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