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wolverine [178]
3 years ago
10

PLS HELP!!

Physics
2 answers:
kirill115 [55]3 years ago
5 0

Answer:

b

Explanation:

Marta_Voda [28]3 years ago
3 0
B..... if the object is falling it decreases cause it’s going down
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Neporo4naja [7]

Answer:

drawing of ear step by step

8 0
4 years ago
the weight of an object on earth is 350 newtons. on mars the same object would weigh 134 newtons. what is the acceleration due t
Eddi Din [679]
Mass will remain constant on both planet, let mass of the object be "m".
let x be the <span>acceleration due to gravity on the surface of mars.
Weight of object on earth = m *g , where g is </span><span>acceleration due to gravity on the surface of earth
</span>⇒350 =  m *  9.8
⇒m = 350  /  9.8                        .............................equation(1)
Weight of object on mars = m * x , where x is acceleration due to gravity on the surface of mars
134  =   m   *  x                           .............................equation(2)
putting the value of m from equation (1) in equation(2) , we get,
x     =   (134  *  9.8) / 350
⇒  x   =   3.572 m/s²
7 0
4 years ago
An unknown object is placed inside of a spherical container and dropped from an airplane. When empty, the spherical container ha
hichkok12 [17]

Answer:

The mass of unknown object is 8.62Kg

Explanation:

To develop this problem it is necessary to apply the equations related to the Drag force and the Force of Gravity.

For the given point, that is, the moment at which the terminal velocity is reached, the two forces equalize, that is,

F_D =F_g

By definition we know that the Drag force is defined as

F_D= \frac{1}{2} C_d \rho A V^2

Where,

C_d = Drag coefficient

\rho =Density

A =Cross-sectional Area

V = Velocity

In the other hand we have,

F_g = (m_1 +m_2) g

Where,

m_1 =Mass of sphere

m_2 =Mass of unknown object

Equating the two equations we have to

(m_1 +m_2) g=\frac{1}{2} C_d \rho A V^2

Re-arrange for m_2,

m_2 = \frac{1}{2g} C_d \rho A V^2 -m_1

Our values are given by,

C_d = 0.5

\rho = 1.22Kg/m^3

V = 66.7m/s

m_1 = 3Kg

d= 32.7*10^{-2}m

r = 16.35*10^{-2}m

Replacing in the equation we have,

m_2 = \frac{1}{2(9.8)}(0.5) (1.22) (\pi*(16.35*10^{-2})^2)*66.7^2 -3

m_2 = 8.62Kg

<em>Therefore the mass of unknown object is 8.62Kg</em>

4 0
3 years ago
Our galaxy is Select one: a. one member of a large cluster of thousands of galaxies. b. one member of a small cluster of galaxie
Art [367]

Answer:

the answer is b

5 0
3 years ago
All points to the blank of zero on a horizontal number line are negative.
sergij07 [2.7K]
All points to the left of zero on a horizontal number line are negative. A  number line<span> is a picture of a graduated straight </span>line<span> that serves as abstraction for real </span>numbers. <span>This </span>number line<span> can be extended to the left to </span>represent numbers<span> which are smaller than </span>0<span>. Such </span>numbers<span> are called negative </span>numbers<span>.</span>
6 0
3 years ago
Read 2 more answers
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