Answer:
6.49 x 10^-8 N
Explanation:
formula is
F= G * ((m1 * m2)/r^2)
F = 6.67x10^-11 * ((6.8*6.8/.218)
F = 6.49 x 10^-8 Newtons
the outermost layer of Earth’s lithosphere that
is found under the oceans and
molded at scattering
centres ono
ceanic ridges, which occur at deviating plate boundaries
Oceanic crust is about 6 km (4 miles) thick.
hope it helps
Answer:

Explanation:
The formula for the force exerted between two charges is

where k is the Coulomb constant.
The charges are identical, so we can write the formula as


Switch because look A switch detects the speed that given device can handle and communicates with it at that speed