Answer:
B. The two sleds will move to the right.
Explanation:
I majored in physics
Answer:
<em>The power generated is = 5.33×10⁸ Watt. </em>
Explanation:
Power: Power can be defined as the time rate of doing work. The S.I unit of power is <em>Watt(W).</em>
<em>Mathematically,</em>
<em>Power (P) = Work done/time or Energy/time</em>
P = mgh/t............................... Equation 1
P = δgh............................. Equation 2
Where δ = fall rate, g = acceleration due to gravity, h = height.
<em>Given: </em>δ = 1.1×10⁶ kg/s, h = 49.4 m g = 9.81 m/s²
Substituting these values into equation 2
P = 1.1×10⁶×49.4×9.81
P = 533.08×10⁶
<em>P = 5.33×10⁸ Watt.</em>
<em>Thus the power generated is = 5.33×10⁸ Watt. </em>
Given Information:
Resistance of circular loop = R = 0.235 Ω
Radius of circular loop = r = 0.241 m
Number of turns = n = 10
Voltage = V = 13.1 V
Required Information:
Magnetic field = B = ?
Answer:
Magnetic field = 0.00145 T
Explanation:
In a circular loop of wire with n number of turns and radius r and carrying a current I induces a magnetic field B
B = μ₀nI/2r
Where μ₀= 4πx10⁻⁷ is the permeability of free space and current in the loop is given by
I = V/R
I = 13.1/0.235
I = 55.74 A
B = 4πx10⁻⁷*10*55.74/2*0.241
B = 0.00145 T
Therefore, the magnetic field at the center of this circular loop is 0.00145 T
Answer:
a) 1.3 rad/s
b) 0.722 s
Explanation:
Given
Initial velocity, ω = 0 rad/s
Angular acceleration of the wheel, α = 1.8 rad/s²
using equations of angular motion, we have
θ2 - θ1 = ω(0)[t2 - t1] + 1/2α(t2 - t1)²
where
θ2 - θ1 = 53.2 rad
t2 - t1 = 7s
substituting these in the equation, we have
θ2 - θ1 = ω(0)[t2 - t1] + 1/2α(t2 - t1)²
53.2 =ω(0) * 7 + 1/2 * 1.8 * 7²
53.2 = 7.ω(0) + 1/2 * 1.8 * 49
53.2 = 7.ω(0) + 44.1
7.ω(0) = 53.2 - 44.1
ω(0) = 9.1 / 7
ω(0) = 1.3 rad/s
Using another of the equations of angular motion, we have
ω(0) = ω(i) + α*t1
1.3 = 0 + 1.8 * t1
1.3 = 1.8 * t1
t1 = 1.3/1.8
t1 = 0.722 s
