HELP ASAP!!! i dont have too much points to give but i really need the help

Mathematics

1 answer:

Rama09 [41]3 years ago

3 0

Answer:

Step-by-step explanation:

When I was 11, I took my first online Algebra 1 class. This experience was totally new to me, I had never simply had to figure out anything by myself, I always had a teacher to explain the problem. Sometimes, when I became frustrated with a problem, I procrastinated and fell behind schedule which lead to later consequences (like missing hanging out with friends). I quickly learned that being persistent and setting my own schedule was necessary to staying on-track.

Time management is crucial to online learning. Since you can choose when to do your online classes, they are convenient to work on but also very easy to ignore when your real classes (classes that have in-class due dates) have actual teachers who will reprimand and embarrass you in front of the whole class if you fail to complete the work.

Another thing I have learned while taking online classes is that taking notes and rereading text is vital to your understanding of the material. If you only skim through a lesson, you won't remember it. Also, if the class provides practice problems or self-check quizzes, always do them to check your understanding.

I am currently taking two online classes, trigonometry and English 1, I sincerely hope that this will help you. Best of luck in your online learning experience!

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tia_tia [17]

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Rational number 7/3 has terminating decimal

vfiekz [6]

Answer:

2.33

Step-by-step explanation:

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at a particular high school, 42% of the students participate in sports and 25% of the students participate in drama. if 53% of t

baherus [9]

The probability that a student participates in both sports and drama is $0.14$ .

<h3>What is the formula for P(AUB), where A and B are any two events?</h3>

If $A$ and $B$ are any two events, then the probability of the joint event $(A\cup B)$ is given by the following formula: $P(A\cup B)=P(A)+P(B)-P(A\cap B)$

Given that 42% of the students participate in sports and 25% of the students participate in drama and 53% of the students participate in either sports or drama.

Suppose $S$ denotes that "a student participates in sports" and $D$ denotes that "a student participates in drama".
So, we have $P(S)=\frac{42}{100}=0.42$ , $P(D)=\frac{25}{100}=0.25$ , $P(S\cup D)=\frac{53}{100}=0.53$ .

We want to find the probability that a student participates in both sports and drama i.e., we want to find $P(S\cap D)$ .

By the above formula, we obtain:

$P(S\cup D)=P(S)+P(D)-P(S\cap D)\\\Longrightarrow P(S\cap D)=P(S)+P(D)-P(S\cup D)\\\Longrightarrow P(S\cap D)=0.42+0.25-0.53\\\therefore P(S\cap D)=0.14=\frac{14}{100}$