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7nadin3 [17]
3 years ago
13

The sum of 14 and Greg's saving is 72

Mathematics
2 answers:
AlexFokin [52]3 years ago
4 0
Hope this helps you..!!

son4ous [18]3 years ago
3 0

Hello!

Let's write this as an equation below, with g representing Greg's savings.

14+g=72

To solve for Greg's savings, we subtract 14 from both sides of our equation.

g=58

Therefore, Greg has saved $58

I hope this helps!

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8 0
3 years ago
Tom has three times as many pencils as pens but has a total of 100 writing utensils. How many pencils does Tom have? How many pe
Genrish500 [490]

Answer:

There are 75 pencils and 25 pens.

Step-by-step explanation:

If Tom has three times as many pencils than pens then,

Pencils = 3(Pens)

If there are a total of 100 writing utensils then,

Pencils + Pens = 100

Substitute the word "pencils" in this equation to 3(Pens),

3(Pens) + Pens = 100

Now remember there is almost a 'hidden' one beside the word "Pens" so,

3Pens + 1Pens = 100

Add the two together,

4Pens = 100

Divide,

Pens = 25

Substitute 25 into the first equation,

Pencils = 3(25)

Pencils = 75

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3 0
3 years ago
The average production cost for major movies is 57 million dollars and the standard deviation is 22 million dollars. Assume the
Degger [83]

Using the normal distribution, we have that:

  • The distribution of X is X \approx (57,22).
  • The distribution of \mathbf{\bar{X}} is \bar{X} \approx (57, 5.3358).
  • 0.0597 = 5.97% probability that a single movie production cost is between 55 and 58 million dollars.
  • 0.2233 = 22.33% probability that the average production cost of 17 movies is between 55 and 58 million dollars. Since the sample size is less than 30, assumption of normality is necessary.

<h3>Normal Probability Distribution</h3>

The z-score of a measure X of a normally distributed variable with mean \mu and standard deviation \sigma is given by:

Z = \frac{X - \mu}{\sigma}

  • The z-score measures how many standard deviations the measure is above or below the mean.
  • Looking at the z-score table, the p-value associated with this z-score is found, which is the percentile of X.
  • By the Central Limit Theorem, the sampling distribution of sample means of size n has standard deviation s = \frac{\sigma}{\sqrt{n}}.

In this problem, the parameters are given as follows:

\mu = 57, \sigma = 22, n = 17, s = \frac{22}{\sqrt{17}} = 5.3358

Hence:

  • The distribution of X is X \approx (57,22).
  • The distribution of \mathbf{\bar{X}} is \bar{X} \approx (57, 5.3358).

The probabilities are the <u>p-value of Z when X = 58 subtracted by the p-value of Z when X = 55</u>, hence, for a single movie:

X = 58:

Z = \frac{X - \mu}{\sigma}

Z = \frac{58 - 57}{22}

Z = 0.05.

Z = 0.05 has a p-value of 0.5199.

X = 55:

Z = \frac{X - \mu}{\sigma}

Z = \frac{55 - 57}{22}

Z = -0.1.

Z = -0.1 has a p-value of 0.4602.

0.5199 - 0.4602 = 0.0597 = 5.97% probability that a single movie production cost is between 55 and 58 million dollars.

For the sample of 17 movies, we have that:

X = 58:

Z = \frac{X - \mu}{s}

Z = \frac{58 - 57}{5.3358}

Z = 0.19.

Z = 0.19 has a p-value of 0.5753.

X = 55:

Z = \frac{X - \mu}{s}

Z = \frac{55 - 57}{5.3358}

Z = -0.38.

Z = -0.38 has a p-value of 0.3520.

0.5753 - 0.3520 = 0.2233 = 22.33% probability that the average production cost of 17 movies is between 55 and 58 million dollars. Since the sample size is less than 30, assumption of normality is necessary.

More can be learned about the normal distribution at brainly.com/question/4079902

#SPJ1

8 0
2 years ago
Can you answer the bottom problem please
Minchanka [31]

This is not the answer, but I want to tell you that I can't see what the problem says. I would help you, but I can't.

7 0
3 years ago
Does anyone know this? Please help! ASAP!!!
Fudgin [204]
The answers:
a=4
b=5
c=6
d=1
8 0
3 years ago
Read 2 more answers
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