Answer:
A number of engine geometry properties and performance parameters obtained from dynamometer testing are given in Table below:
Please calculate:
i) Cylinder bore, bore to stroke ratio, connecting rod to crank radius ratio, and clearance volume in each engine cylinder.
ii) Brake power output at 3800 rpm and the torque output at 6000 rpm.
iii) Brake, indicated and friction mean effective pressures at both 3800 rpm and 6000 rpm.
iv) Brake specific fuel consumption in kg/(kW h) and brake thermal efficiency at 3800 rpm.
v) Volumetric efficiency at 3800 rpm.
vi) Air to fuel ratio and the relative air to fuel ratio at 3800 rpm. Is this a lean or rich mixture?
Engine type Displacement/ size Number of cylinders Stroke length Connecting rod length Compression ratio Maximum brake power6000 rpm Maximum [email protected] 3800 rpm Mass flow rate of fuel 3800 rpm Volumetric flow rate of air 3800 rpm Mechanical efficiency @ 3800 rpm Mechanical efficiency @ 6000 rpm Calorific value of fuel Ambient air temperature Ambient air pressure Specific gas constant for air Gasoline, naturally aspirated, four-stroke 1.329 L 4 (Straight) 85 mm 141 mm 11.5 73 kW 128 N m 3.2 g/s 37.5 L/s 0.88 0.72 46 MJ/kg 10 °C 101.3 kPa 287.1 J/(kg K)
Explanation:
Answer:
Limitation in the level of possible accuracy of the that can be obtained to mainly whole degrees
Explanation:
The angle measurement values are located around the circularly shaped bevel protractor to which a Vernier scale can be attached to increase the accuracy of the angle measurement reading
The accuracy of the bevel protractor is up to 5 arc minutes or 1/12° with the space on the Vernier scale having graduations of 1/12°, such that two spaces on the main scale is 5 arc minutes more than a space on the Vernier scale and the dimensions of the coincidence of the two scale will have an accuracy of up to 1/12°
Therefore, whereby the Vernier scale is damaged, the accuracy will be limited to the accuracy main scale reading in whole degrees.
Answer:
The answer is computer cookies.
Explanation:
Smartness :D
Answer:
the required expression is = 4[ 1 - ]
Explanation:
Given the data in the question;
Q = -0.2[ 1 - ]
ω = 100 rad/s
Torque T = 18 N-m
Electric power input = 2.0 kW
now, form the first law of thermodynamics;
dE/dt = dQ/dt + dw/dt = Q' + w'
dE/dt = Q' + w' ------ let this be equation 1
w' is the net power on the system
w' = -
= T × ω
we substitute
= 18 × 100
= 1800 W
= 1.8 kW
so
w' = -
w' = 2.0 kW - 1.8 kW
w' = 0.2 kW
hence, from equation 1, dE/dt = Q' + w'
we substitute
dE/dt = -0.2[ 1 - ] + 0.2
dE/dt = -0.2 + 0.2 ] + 0.2
dE/dt = 0.2
Now, the change in total energy, increment E, as a function of time;
ΔE =
ΔE =
ΔE =
= 4[ 1 - ]
Therefore, the required expression is = 4[ 1 - ]
it would be a bc its a sqare?well 3d is like you can say a cube 2d is like flat
Explanation: