Total heat rejected by compressor = Heat rejected by compression + Heat rejected by intercooler
Heat rejected by compression :
Q = (y - n)/(y - 1) • W
Q = (y - n)/(y - 1) • R(T2 - T1)/(n - 1) ... (i)
Heat rejected by intercooler :
Q = Cp(T2 - T1) ... (ii)
Sum of (i) and (ii) :
Q = (i) + (ii)
Q = (y - n)/(y - 1) • R(T2 - T1)/(n - 1) + Cp(T2 - T1) ... (iii)
Remember that :
R = Cp - Cv
y = Cp/Cv
So :
R = yCv - Cv
R = Cv(y - 1) ... (iv)
Now, subtitute (iv) to (iii) :
Q = (y - n)/(y - 1) • Cv(y - 1)(T2 - T1)/(n - 1) + Cp(T2 - T1)
Q = (y - n)/(n - 1) • Cv(T2 - T1) + Cp(T2 - T1)
Q = [Cp + Cv • (y - n)/(n - 1)] • (T2 - T1)
Hope this help
The quantity heat loss through below-grade basement walls at a depth of 6-7 feet with no insulation is C. 0.069
<h3>What is insulation?</h3>
Insulation is the process of constructing a barrier between two objects that reduces heat transfer by either reflecting thermal radiation or decreasing thermal conduction and convection from one to the other. The insulation will be more or less effective depending on the material of the barrier.
We can directly see the value of heat loss below grade basement walls at different depth from the handbook of fundamentals.
Heat loss through below grade basement walls at depth of 6-7 ft with no insulation is
= 0.069 BTU/hr.ft.0F (In English units)
Hence option ( C ) is correct.
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Hello! The answer to your question would be as followed:
Crawling in heavy smoke or extreme heat can increase <u><em>visibility</em></u>
Answer:
A voltage divider is a simple series resistor circuit. It's output voltage is a fixed fraction of its input voltage. The divide-down ratio is determined by two resistors.