1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
inna [77]
3 years ago
12

In a 100 mm diameter horizontal pipe, a venturimeter of 0.5 contraction ratio has been fitted. The head of water on the meter wh

en there is no flow is 3 m (gauge). Find the rate of flow for which the throat pressure will be 2m of water absolute. Discharge coefficient for the meter is 0.97.
Physics
1 answer:
nata0808 [166]3 years ago
7 0

Answer:

the rate of flow = 29.28 ×10⁻³ m³/s or 0.029 m³/s

Explanation:

Given:

Diameter of the pipe = 100mm = 0.1m

Contraction ratio = 0.5

thus, diameter at the throat of venturimeter = 0.5×0.1m = 0.05m

The formula for discharge through a venturimeter is given as:

Q=C_d\frac{A_1A_2}{\sqrt{A_1^2-A_2^2}}\sqrt{2gh}

Where,

C_d is the coefficient of discharge = 0.97 (given)

A₁ = Area of the pipe

A₁ = \frac{\pi}{4}0.1^2 = 7.85\times 10^{-3}m^2

A₂ = Area at the throat

A₂ = \frac{\pi}{4}0.05^2 = 1.96\times 10^{-3}m^2

g = acceleration due to gravity = 9.8m/s²

Now,

The gauge pressure at throat = Absolute pressure - The atmospheric pressure

⇒The gauge pressure at throat = 2 - 10.3 = -8.3 m (Atmosphric pressure = 10.3 m of water)

Thus, the pressure difference at the throat and the pipe = 3- (-8.3) = 11.3m

Substituting the values in the discharge formula we get

Q=0.97\frac{7.85\times 10^{-3}\times 1.96\times 10^{-3}}{\sqrt{7.85\times 10^{-3}^2-1.96\times 10^{-3}^2}}\sqrt{2\times 9.8\times 11.3}

or

Q=\frac{0.97\times15.42\times 10^{-6}\times 14.88}{7.605\times 10^{-3}}

or

Q = 29.28 ×10⁻³ m³/s

Hence, the rate of flow = 29.28 ×10⁻³ m³/s or 0.029 m³/s

You might be interested in
A+20 N force acts on a car and at the same time, a -30 N force acts on the
katovenus [111]

Answer:

-10 N, not balanced

Explanation:

Force is a vector quantity, so in order to find the net force on an object, we must use vector addition rule.

This means that if two forces acting on an object along the same line, we have to choose one direction as positive, and write the two forces with the correct sign.

In this problem, we have two forces acting along a line on the car:

- A first force of

F_1 = +20 N

- A second force of

F_2=-30 N

Therefore, the net force on the car is:

\sum F=F_1+F_2=+20 +(-30)=-10 N

Moreover, the net force on an object is said to be "balanced" if it is zero: in this case, it is not zero, so it is not balanced.

5 0
3 years ago
A particle travels 15 times around a 10-cm radius circle in 42 seconds. what is the average speed (in m/s) of the particle?
nikklg [1K]
<span>Circumference = 2 * pi * r 62.8318 = 2 * 3.14159 * 10 cm 62.8318 * 15 rotations / 42 seconds = 22.44 cm / second 22.44 cm / 100 cm per meter = .2244 m / s</span>
7 0
3 years ago
Field lines point straight out from all sides of an object. Which statement best describes the object?
Mashcka [7]
It is positively charged.
8 0
3 years ago
Read 2 more answers
A 60 cm diameter wheel accelerates from rest at a rate of 7 rad/s2. After the wheel has undergone 14 rotations, what is the radi
Mamont248 [21]

Answer:

a=368.97\ m/s^2

Explanation:

Given that,

Initial angular velocity, \omega=0

Acceleration of the wheel, \alpha =7\ rad/s^2

Rotation, \theta=14\ rotation=14\times 2\pi =87.96\ rad

Let t is the time. Using second equation of kinematics can be calculated using time.

\theta=\omega_it+\dfrac{1}{2}\alpha t^2\\\\t=\sqrt{\dfrac{2\theta}{\alpha }} \\\\t=\sqrt{\dfrac{2\times 87.96}{7}} \\\\t=5.01\ s

Let \omega_f is the final angular velocity and a is the radial component of acceleration.

\omega_f=\omega_i+\alpha t\\\\\omega_f=0+7\times 5.01\\\\\omega_f=35.07\ rad/s

Radial component of acceleration,

a=\omega_f^2r\\\\a=(35.07)^2\times 0.3\\\\a=368.97\ m/s^2

So, the required acceleration on the edge of the wheel is 368.97\ m/s^2.

6 0
3 years ago
A train car has a mass of 10,000 kg and is moving at +3.0 m/s. It strikes an identical train car that is at rest. The train cars
jolli1 [7]

Answer:1.5

Explanation:

Edg

7 0
3 years ago
Other questions:
  • A defibrillator passes 14.0 A of current through the torso of a person for 0.0300 s. How much charge moves in coulombs?
    13·1 answer
  • A marble rolls off a table with a speed of 2.30 m/s. If the table is 1.12 m high, how far from the
    10·1 answer
  • Given light with frequencies of: 5.5 x 1014 Hz, 7 x 1014 Hz and 8 x 1014 Hz, calculate the wavelengths in free space. What color
    14·1 answer
  • A 7500-kg rocket blasts off vertically from the launch pad with a constant upward acceleration of 2.25m/s2 and feels no apprecia
    14·1 answer
  • The world record for a 100 m race is 10.44 m/s. How fast is this in mi/h?
    6·1 answer
  • a force of 20 N acted on a ball thereby imparting an impulse of 70 Ns to the ball. For how long did the force act on the ball?
    10·1 answer
  • A 92-kg skier is sliding down a ski slope that makes an angle of 40 degrees above the horizontal direction. the coefficient of k
    5·1 answer
  • How do you calculate Friction force without the coefficient of friction
    11·1 answer
  • A force produces an acceleration of 5 ms
    8·1 answer
  • CAT NOIR YAHHHHHHHHHHHHH
    9·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!