Answer:
B
Explanation:
It will give the of 6 which is least of all the other forces.
4.0²+4.0² = c²

6 = c
We have to covert 512 cal of heat in kilo joules.
As, 1 cal = 0.004184 kJ = 4.184 joules.
Therefore,

Thus, combustion of a small wooden match produces approximately ( in kilo joules ) is 2.142 kJ .
Answer:

Explanation:
Given that,
Initial speed of a car, u = 13 m/s
Final speed of a car, v = 25 m/s
Time, t = 5 s
We need to find the acceleration of the car during this 5.0 second time interval. Let a is the acceleration. It can be calculated as :

So, the acceleration of the car is
.
I attached a picture of the diagram associated with this question.
Now,
When we check the vertical components of the tension in the rope, we will find that we have two equal components acting upwards.
These two components support the weight and each of them has a value of TcosΘ
The net force acting on the body is zero.
Fnet=Force of tension acting upwards-Force due to weight acting downwards
0 = 2TcosΘ -W
W = 2TcosΘ
T = W / 2cosΘ